Which of the following best describes the technique used to graph the equation y = 5x + 10using the slope and y-intercept?

find the center of the circle given the question (×-2)²+(y+6)²=10? A. (2,-6) B. (-2,6) C. (2,6) D. (-2,-6)

White raven [17]

Answer:

A. (2,-6)

Step-by-step explanation:

(×-2)²+(y+6)²=10

Equating it with

(×-h)²+(y -k)²=10

h = 2 & k = - 6

(h, k) = (2, - 6)

5 0

2 years ago

What is the equation

IRINA_888 [86]

Answer:

1+1= 11

1Step-by-step explanation:

I might be wrong so if i am right pls give me a thanks

7 0

3 years ago

Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit

dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252$

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002$

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

$P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240$

iv. Assuming the the 5 pieces of chocolate are of different types, if she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & ORDERED

n = 10 AND k = 5

Total number of combinations becomes

$n^k=10^5=100,000$

Sampling with replacement means that one friend can be sampled more than once i.e: A friend receives a piece of chocolate more than once

The order dictates how the sampling is applied.

3 0

3 years ago

Suppose that an internal report submitted to the managers at a bank in Boston showed that with 95 percent confidence, the propor

Dmitry [639]

Answer:

The sample size used to compute the 95% confidence interval is 1066.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The 95% confidence interval for proportion of the bank's customers who also have accounts at one or more other banks is (0.45, 0.51).

To compute the sample size used we first need to compute the sample proportion value.

The value of sample proportion is:

$\hat p=\frac{Upper\ limit+Lower\ limit}{2}=\frac{0.45+0.51}{2}=0.48$

Now compute the value of margin of error as follows:

$MOE=\frac{Upper\ limit-Lower\ limit}{2}=\frac{0.51-0.45}{2}=0.03$

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the value of sample size as follows:

$MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.03=1.96\times \sqrt{\frac{0.48(1-0.48)}{n}}\\(\frac{0.03}{1.96})^{2}=\frac{0.48(1-0.48)}{n}\\n=1065.404\\n\approx1066$

Thus, the sample size used to compute the 95% confidence interval is 1066.

4 0

2 years ago

The following factors are not prime: (x2- 7x)(7x+21).What remains to be factored? (can be more than one answer). A) Factor out t

topjm [15]

C
The first binomial can have an x factored out, resulting in (x-7) and the second binomial can have a 7 factored out, resulting in (x+3)

5 0

3 years ago

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