Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
5 laps per day
Step-by-step explanation:
30 laps divided by 6 days gives you 5 laps per day.
yesenia has 9 blocks. misty has 15.
15 + 9 = 22.
for the values of the blocks, yesenia has 17 and misty has 68.
17 + 68 = 85.
hope i helped!
Answer:
68.17m
Step-by-step explanation:
Please see attached a rough sketch of the scenario
Step one:
Given data
Height of victim= 4.5ft
The horizontal distance of the snipper from the building = 780ft
The angle of elevation= 5 degrees
Required
The vertical distance
The opposite= the vertical distance
789 ft = the adjacent
Step two:
Applying SOH CAH TOA
tan ∅= opp/adj
tan 5= opp/780
cross multiply we have
0.0874= opp/780
cross multiply we have
0.0874*780= opp
opp= 68.17m
The sniper shoots from a vertical distance of 68.17m
