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kirill115 [55]
3 years ago
7

Which of the following is the complete list of roots for he polynomial function f(x) = (x^2+6x+8)(x^2+6x+13)

Mathematics
2 answers:
stepladder [879]3 years ago
5 0

The complete roots of the function are .Option (C) is correct.

Further explanation:

The Fundamental Theorem of Algebra states that the polynomial has n roots if the degree of the polynomial is n.

The polynomial function has roots or zeroes.

Given:

The function is

Explanation:

To obtain the roots of the polynomial function substitute for either the value of or

Solve the function to obtain the zeroes.

Solve the function to obtain the zeroes.

The roots can be obtained as follows,

The complete roots of the function are Option (C) is correct.

LekaFEV [45]3 years ago
3 0

Answer: the list of roots is {-4, 2, -3+2i, -3-2i}

Use the quadratic formula to get the roots of the two separate terms in brackets:

x^2+6x+8=0 has solutions: -4 and 2

x^2+6x+13=0 has solutions: -3+2i and -3-2i


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Step-by-step explanation:

Each atom of the gas weighs 1.67 ⋅ 10−24 grams. 6.71 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71. ... 0.67 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71 ⋅ 10−1.

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If the measure of angle ABD is 100, what is the measure of angle ABC
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Dimensional <br> 528 feet to miles
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Step-by-step explanation:

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3 years ago
Kip bought one and four sixths pounds of toffee. He gave five sixths of a pound to his friend. How much toffee does Kip have lef
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6 0
2 years ago
Read 2 more answers
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
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