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wolverine [178]
3 years ago
11

One fourth of a box of cereal was shared equally among 3 people. How much cereal did each person get?

Mathematics
2 answers:
just olya [345]3 years ago
6 0
Okay so the problem starts you off with the fraction (1/4). Sharing equally among 3 people would mean that you'd want to divide it by three so your equation would initially look like (1/4) / 3. Having two dividing signs is confusing so what you do is change the dividing into multiplying by the reciprocal of 3 = 1/3... This would make your expression (1/4) * (1/3) and when you simplify this you should get 1/12 as the answer.   
pantera1 [17]3 years ago
4 0
The answer is : 1.33333333 because 4 divided by 3 is 1.33333333 and 1.33333333x1 is 1.33333333 so the answer is 1.33333333
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3.4 mi/h converted into ft/sec<br><br> Please someone help me out on this question!
Vlad [161]

To convert mi/h to ft/sec, multiply it to 1.466.

So 3.4 mi/h x 1.466 = 4.986 ft/sec

5 0
3 years ago
I'm having trouble with this<br><br> -9x + 4y = 55<br> -11x + 7y = 82
lubasha [3.4K]

Answer:

Step-by-step explanation:

99x - 44y = -605

-99x + 63y = 738

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-9x + 28 = 55

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x = -3

(-3, 7)

7 0
3 years ago
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Find the Axis of Symmetry of the following Quadratic, Show all work<br><br> y = x ^2 + 8x + 12
Tanya [424]
The answer should be x = -4
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3 years ago
X+y=26<br> 3x+8y=123<br> What is x equal
Pani-rosa [81]

Answer:

x=17, y=9. (17, 9).

Step-by-step explanation:

x+y=26

3x+8y=123

------------------

x=26-y

3(26-y)+8y=123

78-3y+8y=123

78+5y=123

5y=123-78

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5 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
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