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Trava [24]
3 years ago
12

If mABD​, what are mABC and m​DBC?

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

45

Step-by-step explanation:

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Find the value of x in the triangle shown below.
Alekssandra [29.7K]

Answer:

102 degrees.

Step-by-step explanation:

Because the 3.3's are congruent (the same), this triangle is isosceles.

A property of isosceles means that the two angles are congruent.

39+39= 78

This means that the last angle must be 180-78.

5 0
3 years ago
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the scale of a map is 1 cm : 72km. What is the actual distance between two towns that are 4 cm apart on the map
PolarNik [594]
288km is he distance
4x72 = 288
8 0
3 years ago
3x+6+6x=42 what is x?
tatiyna

Answer:

x = 4

Step-by-step explanation:

Step 1: Combine like terms

9x + 6 = 42

Step 2: Isolate x by subtracting 6 on both sides

9x = 36

Step 3: Isolate x by dividing by 9 on both sides

x = 4

4 0
3 years ago
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PLEASE HELP W/ THIS ASAP!!
Leni [432]

Answer:

- 1.375

Step-by-step explanation:

Each dot is worth -1/8 of a unit when moving left.

So the coordinates of the dark dot are - 1 and - 3/8

or - 1.375 . The word coordinates (plural) bothers me. It all depends on how you have been asked to represent these points. Another possibility is (-1.375,0). You have to choose from the examples you have been given. I wouldn't do that because you have not been given and xy graph.

3 0
3 years ago
The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1). Find the new coordinates of the vertices after the given tra
dybincka [34]

Answer:

<h3>A'(-2,0) , B'(0.5,6) and C'(3,0)</h3>

Step-by-step explanation:

The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1).

The given translation of vertices,

<h3> (x, y) → (x + 3, y − 1)</h3>

This translation shows shift x-coordinate 3 unit right and y-coordinate 1 unit down.

  • First translate vertices A(-5,1)

A(-5,1)\rightarrow A'(-5+3,1-1)

New vertices A'(-2,0)

  • Now vertices B(-2.5,7)

B(-2.5,7)\rightarrow B'(-2.5+3,7-1)

New vertices B'(0.5,6)

  • Now vertices C(0,1)

C(0,1)\rightarrow C'(0+3,1-1)

New vertices C'(3,0)

Hence, the new coordinate of the vertices are A'(-2,0) , B'(0.5,6) and C'(3,0)

4 0
3 years ago
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