Answer:

Generally given that the electric field is negative it mean that its direction is opposite to that of the force
Explanation:
From the question we are told that
The charge on the small object is 
The force is 
Generally the magnitude of the electric field is mathematically represented as

=> 
=> 
Generally given that the electric field is negative it mean that its direction is opposite to that of the force
I need pictures or something
Answer: To focus on a near object – the lens becomes thicker, this allows the light rays to refract (bend) more strongly. To focus on a distant object – the lens is pulled thin, this allows the light rays to refract slightly.
Explanation:
B because I just think it’s the right answer because drawing a PV diagram for this cycle is the best answer even though it might be a stupid so I would not pay attention to my response because I’m just getting this for points but let me know if it is the right answer because right now I’m just guessing.