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PtichkaEL [24]
3 years ago
10

A wagon is pulled at a speed of 0.40 meters/sec by a horse exerting an 1,800-newton horizontal force. what is the power of this

horse?
Physics
1 answer:
Alex787 [66]3 years ago
5 0
The answer is: 720W
The definition of Power is:P =L/t =→F⋅→s/t =→F⋅→s/t = →F⋅→v
The ⋅ in the last formulation designate a scalar product, well-defined by:
→v . →w = |v| |w| cos(ˆvw), the angle ˆvw is 0 because →F and →v are parallel, so the cosinus is 1.
So: P=1800N⋅ 0,40m/s=720W.
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Electromagnetic waves do not require a medium to travel through. They can travel through empty space or matter.
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A coin released at rest from the top of a tower hits the ground after falling 5.7 s. What is the speed of the coin as it hits th
Bad White [126]

Given parameters:

Initial velocity of Coin = 0m/s

Time taken before coin hits ground  = 5.7s

Unknown:

Final velocity of the coin  = ?

Velocity is displacement with time. To solve this problem, we have to apply one of the equations of motion.

The fitting one of them here is shown below;

             V = U + gt

where;

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

t is the time taken

Here we use positive value of acceleration due to gravity because the coin is falling with the effect of acceleration and not against it.

Now input the parameters and solve;

               V  = 0 + 9.81 x 5.7

               V = 55.917m/s

Therefore, the final velocity is 55.917m/s.

8 0
3 years ago
If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add
mr Goodwill [35]

Each Al^+^3 ion contains three extra protons. Hence, the extra charge on each  Al^+^3 = 3 \times 1.6 \times 10^-^1^9 C

Total charge = 0.035 pC

Total charge (Q) = 0.035 \times 10^-^1^2 C

Let the number of Al^+^3 ions be n.

According to question:

n \times 3 \times 1.6 \times 10^-^1^9 =0.035 \times 10^-^1^2

n = \frac{0.035 \times 10^-^1^2}{3 \times 1.6 \times 10^-^1^9}

n = 7.29167 \times 10^4

n = 72917

Hence, the total number of ions needed to be transferred is 72917

3 0
3 years ago
Light of wavelength 500 nm is incident perpendicularly from air on a film 10-4cm thick and of refractive index 1.375. Part of th
Marysya12 [62]

Answer

given,

wavelength (λ)= 500 n m

thickness of film= 10⁻⁴ cm

refractive index = μ = 1.375

distance traveled is double which is equal to 2 x 10⁻⁴ cm

a) Number of wave

     N = \dfrac{d}{\mu\lambda}

     N = \dfrac{2 \times 10^{-6}}{1.375\times 500 \times 10^{-9}}

           N = 2.91

           N = 3

b) phase difference is equal to

Reflection from the first surface has a 180° (½λ) phase change.

There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.

net phase difference = 180^0\times \dfrac{3}{2}

                                   = 270°

6 0
3 years ago
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