At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took
off?
Question 3 options:
200 km
300 km
173 km
224 km
Question 3 options:
200 km
300 km
173 km
224 km
2 answers:
The destination is 224 km from where the plane took off. Therefore correct option is (d).
First the plane turns 100 km North, and than 200 km East. Since both the directions are perpendicular to each other, therefore we can apply the Pythagoras theorem to calculate the distance between the destination and the point where plane took off
=100^{2}+200^{2}
D=223.60 km=224 km
Therefore, The destination is 224 km from where the plane took off
You might be interested in
To solve this problem we will apply the concepts related to the conservation of the Momentum. For this purpose we will define the momentum as the product between mass and velocity, and by conservation the initial momentum will be equal to the final momentum. Mathematically this is,
Here,
= Mass of Dan and Skateboard respectively
= Initial velocity of Dan and Skateboard respectively
= Final velocity of Dan and Skateboard respectively
Our values are:
Dan's mass
Mass of the skateboard
Both have the same initial velocity, then
Final velocity of Skateboard is
Rearranging to find the final velocity of Dan we have then,
Replacing,
Therefore Dan will touch the ground at a speed of 3.76m/s
Answer:
<em>radius of the loop = 7.9 mm</em>
<em>number of turns N ≅ 399 turns</em>
Explanation:
length of wire L= 2 m
field strength B = 3 mT = 0.003 T
current I = 12 A
recall that field strength B = μnI
where n is the turn per unit length
vacuum permeability μ = = 1.256 x 10^-6 T-m/A
imputing values, we have
0.003 = 1.256 x 10^−6 x n x 12
0.003 = 1.507 x 10^-5 x n
n = 199.07 turns per unit length
for a length of 2 m,
number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>
since there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.
this length is also equal to the circumference of each loop
the circumference of each loop =
0.005 = 2 x 3.142 x r
r = 0.005/6.284 = = 0.0079 m =<em> 7.9 mm</em>