At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took
off?
Question 3 options:
200 km
300 km
173 km
224 km
Question 3 options:
200 km
300 km
173 km
224 km
2 answers:
The destination is 224 km from where the plane took off. Therefore correct option is (d).
First the plane turns 100 km North, and than 200 km East. Since both the directions are perpendicular to each other, therefore we can apply the Pythagoras theorem to calculate the distance between the destination and the point where plane took off
=100^{2}+200^{2}
D=223.60 km=224 km
Therefore, The destination is 224 km from where the plane took off
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Answer:
Explanation:
The form of Newton's 2nd Law that we use for this is:
F - f = ma where F is the Force pulling the mass down the ramp forward, f is the friction trying to keep it from moving forward, m is the mass and a is the acceleration (and our unknown).
We know mass and we can find f, but we don't have F. But we can solve for that by rewriting our main equation to reflect F:
That's everything we need.
w is weight: 6.0(9.8). Filling in:
6.0(9.8)sin20 - .15(6.0)(9.8) = 6.0a and
2.0 × 10¹ - 8.8 = 6.0a and
11 = 6.0a so
a = 1.8 m/s/s