Lifting book over your head is what type of energy

if charge is located at center of spherical volume and electric flux through surface of sphere is Φ what would be flux through s

jonny [76]

Answer:

The flux will be nine times as great.

Explanation:

The electric flux due to a charge Q located in the center of a sphere can be obtained using Gauss's law. Considering a Gaussian surface in the form of a sphere of radius r:

$\Phi_E=\int\limits {Ecos\theta dS} \,$

The electric field (E) is parallel to the surface vector (dS), so $\theta=0$

$\Phi_E=\int\limits{Ecos(0)dS} \,\\\Phi_E=E\int\limits{dS} \,\\\Phi_E=ES\\\Phi_E=E4\pi r^2$

Since the electric flux is proportional to the square of the sphere's radius, if radius of sphere were tripled, the flux will be nine times as great.

7 0

3 years ago

5 points

lesantik [10]

Answer:

True

Explanation:

Because everything usually has chemicals

Plz say it's false if i gave out the wrong answer

7 0

3 years ago

What increase in temperature is needed to increase the length of an aluminum meterstick by 1.0 mm?

Fudgin [204]

Answer:

42k

Explanation:

4 0

3 years ago

Derive the following equations of motion

xz_007 [3.2K]

Answer:

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<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

$a = \frac{v - u}{t} \\ or \: at = v - u \\ v = u + at \:$

It is first equation of motion.

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<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

$v = u + at...........(i) \\ s = \frac{u + v}{2} \times t.........(ii)$

Putting the value of v from the equation (i) in equation (ii), we have,

$s= \frac{u + (u + at)}{2} \times t \: \: \\ or \: s = \frac{(2u + at)t}{2} \\ or \: s = \frac{2ut + a {t}^{2} }{2} \\ s = ut + \frac{1}{2} a {t}^{2}$

It is third equation of motion.

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<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

$v = u + at.....(i) \\ s = \frac{u + v}{2} \times t......(ii) \\$

$v = u + at \\ or \: at = v - u \\ t = \frac{v - u}{a}$

Putting the value of t from (i) in the equation (ii)

$s = \frac{u + v}{2} \times \frac{v - u}{a} \\ or \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ or \: 2as = {v}^{2} - {u}^{2} \\ {v}^{2} = {u}^{2} + 2as$

It is forth equation of motion.

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Hope this helps...

Good luck on your assignment..

3 0

3 years ago

What is the half-life of a compound if 75 percent of a given sample of the compound decomposes in 60 min? assume first-order kin

LenKa [72]

The amount left of a given substance can be calculated through the equation,
A = (A0) x 0.5^n/h
From the given scenario,
A/A0 = 0.75 = 0.5*(60/h)
The value of h from the equation is 144.565 minutes.

6 0

4 years ago