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ANTONII [103]
2 years ago
10

Lifting book over your head is what type of energy

Physics
1 answer:
AleksandrR [38]2 years ago
8 0

Answer:

potential energy

Explanation:

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Realiza la siguiente conversión de unidades: 340 N a Kgf
OleMash [197]

Answer:

The answer is 34.67 kilograms force

3 0
3 years ago
Occupants in a single space shuttle in orbit feel weightless. describe a scheme whereby occupants in a pair of shuttles (or even
agasfer [191]
The   scheme  whereby occupants  in  a  pair  of  shuttles is  as  follows
use  a  strong  cable  with  large  weight  on  the  end
Then  use  the  orbital  naneuvering   system(OMS)  to   set  the   whole  work  as  spinning   about   their  common  center of  gravity.
8 0
3 years ago
n outer space, a constant net force with a magnitude of 140 N is exerted on a 32.5 kg probe initially at rest. A) What accelerat
musickatia [10]

Answer:

a) 4.31 m/s²

b) 215.5 m

Explanation:

a) According to Newton's first law of motion

The net force applied to particular mass produced acceleration, a, according to

F = ma

F = 140 N

m = 32.5 kg

a = ?

140 = 32.5 × a

a = 140/32.5 = 4.31 m/s²

b) Using the equations of motion, we can obtain the distance travelled by the object in t = 10 s

u = initial velocity of the probe = 0 m/s (since it was initially at rest)

a = 4.31 m/s²

t = 10 s

s = distance travelled = ?

s = ut + at²/2

s = 0 + (4.31×10²)/2 = 215.5 m

7 0
3 years ago
What is the acceleration of a race car if it has a mass of 1200kg and is moving with an engine force of 400N
meriva

Answer:

0.34 m/s^2

Explanation:

force=mass × acceleration

400 =1200 × acceleration

acceleration=400/1200

=0.34 m/s^2

5 0
2 years ago
A(n) 1100 kg car is parked on a 4◦ incline. The acceleration of gravity is 9.8 m/s 2 . Find the force of friction keeping the ca
igomit [66]

Answer:

Force of friction, f = 751.97 N

Explanation:

it is given that,

Mass of the car, m = 1100 kg

It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.

From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.

f=mg\ sin\theta

f=1100\ kg\times 9.8\ m/s^2\ sin(4)

f = 751.97 N

So, the force of friction on the car is 751.97 N. Hence, this is the required solution.

3 0
3 years ago
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