Answer:
Explanation:
Two straight wires
Have current in opposite direction
i1=i2=i=2Amps
Distance between two wires
r=5mm=0.005m
Length of one wire is ∞
Length of second wire is 0.3m
Force between the wire,
The force between two parallel currents I1 and I2, separated by a distance r, has a magnitude per unit length given by
F/l = μoi1i2/2πr
F/l=μoi²/2πr
μo=4π×10^-7 H/m
The force is attractive if the currents are in the same direction, repulsive if they are in opposite directions.
F/l = μoi1i2/2πr
F/0.3=4π×10^-7×2²/2π•0.005
F/0.3=1.6×10^-4
Cross multiply
F=1.6×10^-4×0.3
F=4.8×10^-5N
Answer:
A dominant allele produces a dominant trait in individuals who have one copy of the allele, that can come from one parent. To produces a recessive trait, the child must have two copies of the recessive allele, one from each parent.
Explanation:
The terms dominant and recessive describe the patterns of certain traits. They describe how likely it is for certain traits to pass from parent offspring in humans and animals. The two copies of each gene (alleles), can be slightly different from each other. The differences can cause variations in the protein that’s produced, Proteins affect traits, so variations in protein activity or expression can create different phenotypes.
A dominant allele produces a dominant phenotype (trait) in individuals who have one copy of the allele, which can come from one parent. For a recessive allele to produce a recessive phenotype, the individual must have two copies, one from each parent. A person with one dominant and one recessive allele for a gene will have a dominant phenotype. They are generally considered carriers of the recessive allele- the recessive allele is there, but the recessive phenotype is not.
Answer:
Vf = 41.6 [m/s]
Explanation:
To solve this problem we must use the equations of kinematics.
Vf² = Vo² + (2*g*y)
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
y = height = 88.2 [m]
Note: The positive sign of the equation tells us that the acceleration of gravity goes in the direction of motion.
Vf² = Vo² + (2*g*y)
Vf² = 0 + (2*9.81*88.2)
Vf = (1730.48)^0.5
Vf = 41.6 [m/s]
Answer:
La masa de la mascota es de 11,24 kg.
Explanation:
Dado que la masa total de = 80 kg
Tenemos
Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N
La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona
Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3
La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota
1/2 × m × 6² = (80 - m) × 9.81 × 0.3
20943 · m = 235440
m = 235440/20943 = 11,24 kg
Terminal speed=136.7 m/s
the formula for the terminal speed is given by :
V= 
m= mass=75 kg
a= area=0.2 x 0.4=0.08 m²
ρ= density of air=1.23 kg/m³
C= drag constant =0.8
so V= 
v= 136.7 m/s
