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Whitepunk [10]
3 years ago
13

Una persona y su perro se encuentran inicialmente en reposo y paradas arriba de una caja que está apoyada sobre un piso rugoso.

La masa total de la caja, la persona y la mascota es de 80 kg. El coeficiente de rozamiento cinético entre la caja y el piso vale 0,3. Cuando el perrito salta hacia el piso con una velocidad horizontal de 6,0 m/s, la caja y la persona se desplazan 1,0 m en sentido contrario. ¿Cuál es la masa de la mascota?
Physics
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

La masa de la mascota es de 11,24 kg.

Explanation:

Dado que la masa total de = 80 kg

Tenemos

Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N

La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona

Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3

La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota

1/2 × m × 6² = (80 - m) × 9.81 × 0.3

20943 · m = 235440

m = 235440/20943 = 11,24 kg

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OPTIONS :

A.) the force that the ball exerts on the wall

B.) the frictional force between the wall and the ball

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Explanation: The normal force acting on an object can be explained as a force experienced by an object when it comes in contact with a flat surface. The normal force acts perpendicular to the surface of contact.

In the scenario described above, Erica's tennis ball experiences an opposite reaction after hitting the wall.This is in relation to Newton's 3rd law of motion, which states that, For every action, there is an equal and opposite reaction.

The reaction force in this case is the normal force exerted on the ball by the wall perpendicular to the surface of contact.

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Rasek [7]

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If the same fish is attached to the end of the unstretched spring and then allowed to fall from rest, through what maximum dista
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Answer:

x=2d

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y= h+ut-\frac{1}{2}gt^2

where

h = 4 m is the initial height of the ball

u = 12 m/s is the initial velocity of the ball (upward)

g = 9.8 m/s^2 is the acceleration of gravity (downward)

We can find the time t at which the ball reaches the ground by substituting y=0 into the equation:

0 = 4 + 12t - 4.9 t^2

This is a second-order equation. By solving it for t, we find:

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v=u-gt

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g = 9.8 m/s^2 is the acceleration of gravity (downward)

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By subsisuting t = 2.75 s, we find the velocity of the ball as it reaches the ground:

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Answer:

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