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3 years ago

A (an) __helps lessen the effects of thermal pollution

Physics

2 answers:

Goryan [66]3 years ago

5 0

Answer:

Tree

Explanation:

It gets rid of the the degrading water temperature by blocking the sun's heat

Hunter-Best [27]3 years ago

4 0

Explanation:

The following measures can be taken to prevent or control high temperature caused by thermal pollution:

1. Heated water from the industries can treated before discharging directly to the water bodies.

2. Heated water from the industries can be treated by the installation of cooling ponds and cooling towers.

3. Industrial treated water can be recycled for domestic use or industrial heating.

4. Through artificial lakes: In this lake Industries can discharge their used or heated water at one end and water for cooling purposes may be withdrawn from the other end. The heat is eventually dissipated through evaporation.

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According to the big bang theory, the universe is continually getting

oee [108]

The answer on Edge would be (A.)= Larger and Cooler ! I'm doing the same thing as y'all. Good luck everyone.

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3 years ago

Read 2 more answers

A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the g

aliina [53]

Given:

P1 = 400 kPa
T1 = 110 K

T2 = 235K

Required:

Solution:

Apply Gay-Lussac’s law where P/T = constant

P1/T1 = P2/T2

P2 = T2P1/T1

P2 = (235K)(400kPa) / (110K)

P2 = 855 kPa

4 0

3 years ago

If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the ac

Neporo4naja [7]

Answer:

A.) V = 14 m/s

B.) h = 36.6 m

Explanation:

Given the formula v = √2gh

where g = 9.8m/sec^2 is the acceleration due to gravity.

A.) Determine the impact velocity for an object dropped from a height of 10 m.

Substitute height h in the given formula

V = √2gh

V = √2 × 9.8 × 10

V = √196

V = 14 m/s

b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.

Substitute the velocity in the given formula and make height h the subject of formula.

26.8 = √2 × 9.8 × h

Square both sides

718.24 = 19.6h

h = 718.24 / 19.6

h = 36.64 m

h = 36.6 m

5 0

3 years ago

To clearly see an image, the wavelength used must be at most 1/4 of the size of the object that is to be imaged. what frequency

LuckyWell [14K]

From the statement, the wavelength should be 1.6 cm * 1/4 = 0.4 cm. Then, we use the wave equation formula. The frequency is equal to the speed of light divided by the wavelength. First, let's use the SI units.

0.4 cm = 0.004 m

The speed of light is equal to 3 x 10^8 m/s

Frequency = 3 x 10^8 m/s ÷ 0.004 m
Frequency = 7.49 x 10^10 s^-1

5 0

3 years ago

A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw

serious [3.7K]

20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma where, F = Force (Newton)

m= mass

a = acceleration

Given:

mass of rocket = M = 1500 kg

acceleration of rocket = a = 10 m/s²

elapsed time = t = 2.00 s

mass of lighter fragment = m₁ = m = 500 kg

mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at