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Natali5045456 [20]
3 years ago
13

A class has 10 boys and 12 girls. in how many ways can a committee of four be selected if the committee can have at most two gir

ls?
Mathematics
1 answer:
V125BC [204]3 years ago
5 0
<span> C(12,0)C(10,4)+C(12,1)C(10,3)+C(12,2)C(10,2) = (1)(210)+(12)(120)+(66)(45) = 210+1440+2904 = 4554 Answeer: 4554 ways</span>
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6.8x+9.3 = -9.4+3,4(2-5x)<br> 6.8x+9.3 = -9.4+6.8 -17<br> 6.8x+9.3 = -2.6-17x
Advocard [28]

Answer:

x = -0.5

Step-by-step explanation:

From your last step:

6.8x + 9.3 = -2.6 - 17x

We have two terms with x in them on different sides of the equation, so we want to bring the 'x terms' over to the same side.

Add 17x to both sides of the equation.

6.8x + 17x + 9.3 = -2.6

Collect like terms

23.8x + 9.3 = -2.6

Subtract 9.3 from both sides

23.8x = -2.6 - 9.3

23.8x = -11.9

Divide both sides by 23.8

x = -0.5

7 0
3 years ago
What is m less than 8 thirds greater than or equal to negative 19
Natalija [7]

Answer:

greater then tell me if i'm wrong

6 0
3 years ago
¿que opinas de las personas que no bautizan a sus hijos?
ioda

Answer:

En el bautismo moderno de un bebé o un niño, el padrino o los padrinos hacen una profesión de fe para la persona que se bautiza (el ahijado) y asumen la obligación de actuar como apoderados de los padres si los padres no pueden o se niegan a mantener. la formación religiosa del niño

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2 years ago
Anybody help me please
GrogVix [38]

Answer:

Rotation 180° counterclockwise about the origin

7 0
3 years ago
Read 2 more answers
What are all of the rational zeros of the function g(x) = x^4- x^3+ 4x^2- 4x?
Darya [45]

Yo sup??

We can solve this questions by trying option verification.

We observe that 0 is common among all the options so 0 has to be a zero of the function.

when x=1

g(1)=1-1+4-4=0

Therefore 1 is also a zero of the function.

Since 1 is not there is option 2 and 3, hence our answer is either option 1 or 4

when x=2

g(2)=16-8+16-8=0

Therefore 2 is also a zero of the function.

Hence the correct answer is option D ie 0,1,2

Hope this helps.

6 0
3 years ago
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