Answer:
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
Step 1:
(a + x) (ax + b)
Step 2: Proof
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
Step 3: Proof
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found .
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
B.
Mean: 208.08
Median: 224.4
Mode: 122.4
Range: 183.6
First, we can make it easier by rearranging them from least to greatest in proper numerical form.
$120, $120, $220, $260, $300
Mean: (120 + 120 + 220+ 260 + 300)(1/5)=1020
1020 x 1.02( tax rate) = 1040.4
1040.4/5= 208.08
Median: %220 x 1.02= 224.4
Mode: 120 x 1.02 = 122.4
Range: (300 x 1.02)-(120 x 1.02)= 306-122.4
306 - 122.4 = 183.6
I think the answer is
5fy+7f
5=30-3=27+-36=-9 amswers negfative 9
