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Lina20 [59]
3 years ago
14

What is the sum or difference 2^4-8^4

Mathematics
2 answers:
malfutka [58]3 years ago
4 0
<span>-4080 is the correct answer

</span>
emmasim [6.3K]3 years ago
4 0

2^4-8^4

16-8^4

16-4096

= -4080


I hope that's help !

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If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
Marizza181 [45]

First, we will find the value of k

We can do this by sybstituting y=24, x=6 in;

y=kx and then solve for k

24= k(6)

divide both-side of the equation by 6

24/6 = k

4 = k

k=4

Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y

y= (4)(5)

y = 20

7 0
1 year ago
On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?
Nata [24]

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of  students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%

Hence, the approximate absentee rate that day would be 8.09%.

5 0
3 years ago
The question is the photo
Readme [11.4K]
For this question you can say:
5/9( °F - 32) = -10 °C
so now you should solve the equation:
5F/9 - 160/9 = -10 
⇒ 5F/9 = -10 + 160/9 ⇒ 5F/9 = -90/9 + 160/9 ⇒ 5F/9 = 70/9 ⇒ now you can multiply both sides of the equation by 9 so you will have:
5F = 70 ⇒ F = 14 ° F :)))
i hope this is helpful
have a nice day 
6 0
3 years ago
1/4 + 1/3= {Khan Academy btw}
zmey [24]

Answer: \frac{7}{12}

Step-by-step explanation:

\frac{1}{4} +\frac{1}{3}=\frac{(1)(3)+(4)(1)}{(4)(3)}  =\frac{3+4}{12} =\frac{7}{12}

5 0
3 years ago
What is 2.6 * 10 ^ 5 written in standard notation? A. 26, 000 O B. 2, 060, 000 O C. 20,600 O D. 260, 000 O E. 2, 600, 000 O F. 2
noname [10]

Answer:260000

Step-by-step explanation:

4 0
3 years ago
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