<h3>
Answer:</h3>
H+ contains 1 proton, 0 neutrons, 0 electrons.
<h3>
Explanation:</h3>
- An atom is the smallest particle of an element that can take part in a chemical reaction.
- Atoms are made of sub-atomic particles neutrons and protons found in the nucleus and electrons found in the energy levels.
- A hydrogen atom contains 1 proton and 0 neutrons in the nucleus and 1 electron in the energy levels.
- A hydrogen atom loses an electron to form an ion with 1 proton, 0 neutron and 0 electron.
Answer: Between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli.
The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).
ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.
A for the first and b for the second!!:))
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume of gas = 804 mL
Initial temperature = 27°C (27+273=300 K)
Final temperature = ?
Final volume = 402 mL
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 402 mL × 300 K / 804 mL
T₂ = 120,600 mL.K / 804 mL
T₂ = 150 K
