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kotykmax [81]
3 years ago
10

In what sense is the wave motion of a guitar string analogous to the motion of an electron in an atom?

Chemistry
1 answer:
STALIN [3.7K]3 years ago
7 0

Explanation:

A guitar string vibrates when we strikes it. It starts vibrating in several modes simultaneously. It stretches between the saddle and the nut. This distance represents one-half wavelength.

Now if we consider that the string forms a circle, then we have an interpretation of an electron which vibrates in the orbit surrounding the nucleus. We are aware that electrons have wavelength. If the circumference of the orbit happens to be the integer multiple of wavelength , then the orbit is "allowed" since "the electron will retraces its own path."

This explains the line spectrum and not a continuous spectrum.

A line spectrum refers an electron that jumps between the specific energy levels, thus producing only specific colors.

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What is the final volume of 20L of gas at 300K that is heated to 600K at constant pressure?
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Answer:

40

Explanation:

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Materials: • One disposable plastic cup • One disposable plastic spoon (plastic fork or knife may be used instead) • Thermometer
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I'm not sure what the question is, this is a lab proecdure
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In the context of the 4ps of the marketing mix, high-tech media options like cell phones and the internet have had a huge impact
mina [271]

In the context of the 4ps of the marketing mix, high-tech media options like cell phones and the internet have had a huge impact on products.

The four Ps represent the crucial factors that must be carefully thought out and put into practice in order to properly advertise a good or service. Product, price, place, and promotion make up this list.

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Also on how the good or service is perceived in society, and how it distinguishes itself from the competition, and how the business that makes it engages with its clients.

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8 0
1 year ago
5x-13 =12 write description that represents the equation
KiRa [710]

Answer:

x = 5

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25 = 5x

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3 0
3 years ago
Read 2 more answers
A compressor takes 0.50 m3 of a gas at 33°C and 760 mm Hg and compresses it to 0.10 m3, cooling it to -55°C at the same time. Wh
weqwewe [10]

The pressure of the gas is 2700 mmHg.

To solve this problem, we can use the <em>Combined Gas Laws</em>:

(<em>p</em>_1<em>V</em>_1)/<em>T</em>_1 = (<em>p</em>_2<em>V</em>_2)/<em>T</em>_2

<em>p</em>_2 = <em>p</em>_1 ×<em> V</em>_1/<em>V</em>_2 × <em>T</em>_2/<em>T</em>_1

<em>T</em>_2 = (-55+273.15) K = 218.15 K; <em>T</em>_1 = (33+273.15) K = 306.15 K

<em>p</em>2 = 760 mmHg × (0.50 m^3/0.10 m^3) × (218.15 K/306.15 K) = 2700 mmHg

5 0
3 years ago
Read 2 more answers
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