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3 years ago

In what sense is the wave motion of a guitar string analogous to the motion of an electron in an atom?

Chemistry

1 answer:

STALIN [3.7K]3 years ago

7 0

Explanation:

A guitar string vibrates when we strikes it. It starts vibrating in several modes simultaneously. It stretches between the saddle and the nut. This distance represents one-half wavelength.

Now if we consider that the string forms a circle, then we have an interpretation of an electron which vibrates in the orbit surrounding the nucleus. We are aware that electrons have wavelength. If the circumference of the orbit happens to be the integer multiple of wavelength , then the orbit is "allowed" since "the electron will retraces its own path."

This explains the line spectrum and not a continuous spectrum.

A line spectrum refers an electron that jumps between the specific energy levels, thus producing only specific colors.

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How many moles of AIC3 are there in 1,119.972 g ?

Alchen [17]

Answer:

it is 8.40189 moles of AlCl3

mole = mass/molar mass

mole= 1119.972/133.34

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3 years ago

Which of the following is an example of genetic engineering

Alla [95]

Answer:

B: Inserting a gene from a flounder into salmon DNA to produce antifreeze proteins.

Explanation:

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3 years ago

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Which of the following molecules are considered inorganic?

Oksi-84 [34.3K]

The answer is D water

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2 years ago

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Answer asap with at least 3 or more sentences!

mixas84 [53]

Answer:

no.

Explanation:

The reason this has

never happened is due to the source of magnetic fields: moving electric

charges. When electric charges (e.g. electrons) move in circles, they

produce a magnetic field. In a piece of iron, it is very easy to line up

these circles, getting all the little magnets to work together as one big

magnet.

For each of these circles, one side is the north pole and one side is the

south pole. Since each circle has two sides, each circle has a north and a

south pole. Even the smallest possible magnets (spinning electrons) have a

north and a south pole.

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3 years ago

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago