45.6 mL of 0.0600 M of
is added to 25.0 mL of HCl of unknown concentration then , the concentration of HCl is 0.032 M .
Calculation ,
Formula used :
=
...( 1 )
Where
= concentration of
= 0.0600 M ( given )
= concentration of HCl = ? ( to be find )
= volume of
= 25.0 mL ( given )
= volume of HCl = 45.6 mL ( given )
Now , put the value of all volume and concentration in equation ( 1 ) we get .
0.0600 M × 25.0 mL =
× 45.6 mL
= 0.0600 M × 25.0 mL / 45.6 mL = 0.032 M
Therefore , concentration of unknown concentration of HCl is 0.032 M .
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Answer:
0,1 mol of carbon and 0.2 moles of hydrogen were in the original sample.
Explanation:
The combustion reaction of the compound is

And the molar mass of CO2 and H2O are 44g/mol and 18g/mol respectively
All the mass of carbon producing the CO2 must come from the carbon of the unknown compound, thus it is necessary to calculate the moles of carbon in 4.4g of CO2
of Carbon
Also, all the mass of hydrogen producing the H2O must come from the hydrogen of the unknown compound, hence it is necessary to calculate the moles of hydrogen in 1.8g of water
of Hydrogen
HBrO2 is weaker than HClO2.
The structure of n‑methyl‑2‑pyrrolidone when it is heated with aqueous acid. product is given below
<h3 /><h3>What is aprotic solvent?</h3>
A polar solvent without an acidic proton is known as a polar aprotic solvent. These solvents don't include hydroxyl or amine groups. These solvents can act as proton acceptors, but unlike protic solvents, they do not act as proton donors in hydrogen bonding.
After being exposed to a strong aqueous acidic media and being heated, N-methyl-2-pyrrolidone opens up, forming a molecule with a carboxylic group at one end and a protonated nitrogen atom with a methyl group connected to it at the other.
Alcohol, water, hydrogen fluoride, formic acid, acetic acid, ammonia, methanol, ethanol, and other well-known substances are a few examples of polar protic solvents. Polar aprotic solvents, on the other hand, lack acidic protons and do not function as donors during hydrogen bonding.
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