Given :
A 250 ml beaker weighs 13.473 g .
The same beaker plus 2.2 ml of water weighs 15.346 g.
To Find :
How much does the 2.2 ml of water, alone, weigh .
Solution :
Now, mass of water is given by :
Therefore , mass of 2.2 ml of water alone is 1.873 g .
Hence , this is the required solution .
Answer:
ΔT = 0.78 °C
Explanation:
Given data:
Mass of Al = 9.5 g
Specific heat capacity of Al = 0.9 J/g.°C
Temperature change = ?
Heat added = 67 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
67 J = 9.5 g × 0.9 j/g.°C × ΔT
67 J = 85.5 j/°C × ΔT
ΔT = 67 J / 85.5 j/°C
ΔT = 0.78 °C
hope it helps you .............
<span> endothermic is the answer
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1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.
d(H) = 10 nm; diameter of hydrogen atom.
d(H) = 10 nm · 0.001 µm/nm.
d(H) = 0.01 µm = 10⁻² µm.
2) 1 nm = 10⁻⁹ m
; one meter is equal to 0.0000000001 (10⁻⁹) meter.
d(H) = 10 nm.
d(H) = 10 nm · 10⁻⁹ m/nm.
d(H) = 0.00000001 m = 10⁻⁸ m.
3) 1 nm = 10⁻⁶ mm
; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.
d(H) = 10 nm · 10⁻⁶ mm/nm.
d(H) = 0.00001 mm = 10⁻⁵ mm.
