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4 years ago

6

I tried to solve for it 3 times but I still got it wrong. HELP?!?!

1 answer:

QveST [7]4 years ago

3 0

The answer is = 793.00m

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A stone is dropped from the roof of a high building. a second stone is dropped 1.50 s later. how far apart are the stones when t

Aleksandr [31]

2nd stone time = 13.0/9.8 = 1.33 seconds

distance = 0.5*9.8*1.33^2 = 8.67 meters

1st stone time = 1.33+1.5 = 2.83 seconds

distance = 0.5*9.8*2.83^2 = 39.24 meters

39.24-8.67 = 30.57 meters apart

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3 years ago

Four forces of magnitude 10N,15N, 4N, 6N act on on object in the direction North West, East and South respectively, find their m

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3 years ago

Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres i

Dennis_Churaev [7]

Answer:

Angular momentum of the system is 4.8 kg m^2/s

Explanation:

As we know that the angular momentum of the system of masses is given as

$L = 2I\omega$

here we have

$I = m(0.2 + 0.4)^2$

$I = 3(0.6)^2$

now we also know that

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$0.6 \omega = 2 m/s$

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3 years ago

Two small conducting point charges, separated by 0.4 m, carry a total charge of 200 C. They repel one another with a force of 12

Lunna [17]

Answer:

200 C

Explanation:

Let C1 and C2 be their charges. According to Coulomb's law

$F_C = k\frac{C_1C_2}{R^2}$

where k = $8.99\times10^9 nm^2/C^2$ is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force

$120 = 8.99\times10^9\frac{C_1C_2}{0.4^2}$

$C_1C_2 = \frac{120*0.4^2}{8.99\times10^9} = 2.13\times10^{-9}$

Since their total charge is 200C:

$C_1 + C_2 = 200$ or $C_1 = 200 - C_2$

We can substitute the above equation

$C_1C_2 = (200 - C_2)C_2 = 2.13\times10^{-9}$

$-C_2^2 +200C_2 - 2.13\times10^{-9} = 0$

$C= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$C= \frac{-200\pm \sqrt{(200)^2 - 4*(-1)*(-0.00000000213)}}{2*(-1)}$

$C= \frac{-200\pm200}{-2}$

$C = 1.06 \times 10^{-11}$ or $C \approx 200$

So the larger charge is C = 200 C

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4 years ago

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3 years ago