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9 months ago

Solenoid is wound with 2000 turns per meter when the current is 5.2 a, what is the magnetic field within the solenoid?

Physics

1 answer:

Drupady [299]9 months ago

7 0

The magnetic field within the solenoid is 0.013T

<h3>What is Solenoid ?</h3>

An electromagnet known as a solenoid creates a regulated magnetic field using a helical coil of wire whose length is significantly higher than its diameter. When an electric current is sent through the coil, it may create a consistent magnetic field inside a defined region of space.

A solenoid operates by creating an electromagnetic field surrounding an armature, which is a moving core. The electromagnetic field causes the armature to move, and when it does, it opens and closes valves or switches, converting electrical energy into mechanical motion and force.

The magnetic field within the solenoid can be calculated by the expression given below.

Write the expression for magnetic field within the solenoid.

B = u₀nI

B = 4π * 10⁻⁷ * 2000 * 5.2

= 0.013 T

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2 years ago

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<h2>Answer:</h2>

1000th multiple of the standard reference level for intensities.

<h2>Explanation:</h2>

The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;

β = 10 log (I / I₀) --------------------(i)

Where;

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Given from the question;

β = sound level = 30dB

Substitute this value into equation (i) as follows;

30 = 10 log (I / I₀)

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Take antilog of both sides;

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Solve for I;

I = 1000I₀

Therefore the intensity of the sound is 1000 times the standard reference level for intensities (I₀)

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