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3 years ago

PLEASE HELP!!! I WILL RATE BRAINLIEST TO THE FASTEST AND CORRECT ANSWER!!!

Mathematics

1 answer:

Andrej [43]3 years ago

5 0

Not easy:

- 4 < x^4 + 4x^2 ---> 0 < x^4+4x^2+4 = (x^2+2)^2, so it is always positive. Always satisfied. Curious ...

Now the other one:

x^4+4x^2<21 --> x^4+4x^2-21 < 0 --> (x^2+2)^2 - 25 < 0

(x^2+2)^2<25 ->>> x^2+2 < 5 ---> x^2 <3,

So -sqrt(3)<x<sqrt(3) is the answer! Brainliest?

You might be interested in

If the length of AC equals 18, what is the length of the midsection DE

Free_Kalibri [48]

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

The midsegment is the segment which joining the midpoints of two opposite sides of it

The length of the midsegment is half the length of the third side in the triangle which opposite to it

<em>Let us use this rule to solve our question</em>

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

7 0

3 years ago

Which of the tables represents a function? (5 points)

AlladinOne [14]

Answer:

It's table D

Step-by-step explanation:

I just took the test.

3 0

3 years ago

Jane made a door frame for the house but does not have a tool to measure the angles. How can she check that the corner is 90 deg

Marina CMI [18]

Answer:

don't know sorry

Step-by-step explanation:

dont know sorry

5 0

3 years ago

What is the answer of the expression<br> 325-[4x(58-19)+(75 divided by 3

inna [77]

325 - [4(58 - 19) + (75 / 3)]

Divide:

325 - [4(58 - 19) + 25]

Distribute 4:

325 - [232 - 76 + 25]

Subtract:

325 - [156 + 25]

Add:

325 - [181]

Subtract:

144

4 0

3 years ago

A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}$

what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

3 0

3 years ago