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Studentka2010 [4]
3 years ago
7

PLEASE HELP!!! I WILL RATE BRAINLIEST TO THE FASTEST AND CORRECT ANSWER!!!

Mathematics
1 answer:
Andrej [43]3 years ago
5 0
Not easy:

- 4 < x^4 + 4x^2 ---> 0 < x^4+4x^2+4 = (x^2+2)^2, so it is always positive. Always satisfied. Curious ...

Now the other one:

x^4+4x^2<21 --> x^4+4x^2-21 < 0 --> (x^2+2)^2 - 25 < 0

(x^2+2)^2<25 ->>> x^2+2 < 5 ---> x^2 <3,

So -sqrt(3)<x<sqrt(3) is the answer! Brainliest?
You might be interested in
If the length of AC equals 18, what is the length of the midsection DE
Free_Kalibri [48]

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

  • The midsegment is the segment which joining the midpoints of two opposite sides of it
  • The length of the midsegment is half the length of the third side in the triangle which opposite to it

<em>Let us use this rule to solve our question</em>

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

7 0
3 years ago
Which of the tables represents a function? (5 points)
AlladinOne [14]

Answer:

It's table D

Step-by-step explanation:

I just took the test.

3 0
3 years ago
Jane made a door frame for the house but does not have a tool to measure the angles. How can she check that the corner is 90 deg
Marina CMI [18]

Answer:

don't know sorry

Step-by-step explanation:

dont know sorry

5 0
3 years ago
What is the answer of the expression<br> 325-[4x(58-19)+(75 divided by 3
inna [77]
325 - [4(58 - 19) + (75 / 3)]

Divide:

325 - [4(58 - 19) + 25]

Distribute 4:

325 - [232 - 76 + 25]

Subtract:

325 - [156 + 25]

Add:

325 - [181]

Subtract:

144
4 0
3 years ago
A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad &#10;\begin{cases}&#10;1994\impliedby \textit{year 0, starting point}\\&#10;t=0\qquad P=182&#10;\end{cases}\implies 182=ae^{k0}&#10;\\\\\\&#10;182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a&#10;\\\\\\&#10;thus\qquad P=182e^{kt}\\\\&#10;-------------------------------\\\\

\bf P=182e^{kt}\qquad &#10;\begin{cases}&#10;2002\impliedby \textit{8 years later}\\&#10;t=8\qquad P=186&#10;\end{cases}\implies 186=182e^{k8}&#10;\\\\\\&#10;\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k&#10;\\\\\\&#10;\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
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