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bogdanovich [222]
3 years ago
12

An outside thermometer reads -5 degrees at 8:00 a.m. By 12:30 p.m. the temperature outside has increased by 11 degrees. At 12:30

p.m. the temperature inside Susan's house is is 7 degrees more than 11 times the outside temperature. What was the temperature inside the house then.
Mathematics
1 answer:
Lesechka [4]3 years ago
7 0

Answer:

73 degrees.

Step-by-step explanation:

So, let's see the information provided in the question.

At 8 AM, the thermometer was reading -5 degrees.

At 12:30 PM, the temperature has increased by 11 degrees, so it's now +6 degrees outside.

Inside Susan's house, the temperature is 7 degrees more than 11 times the outside temperature, at 12:30 PM.

So, we know the outside temperature at 12:30 PM is +6 degrees.

11 times 6 = 66 degrees.

Then we add the additional 7 degrees, to get a total of 73 degrees.

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Domain stays the same while the range changes

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If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

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G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

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So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0
3 years ago
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

3 0
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