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3 years ago

Factorise -x^4 - (x-z)^4

1 answer:

4 0

\left[x _{4}\right] = \left[ \frac{z}{2}+i \,\sqrt{\frac{1}{2}}\,\sqrt{\left( \frac{3\,z^{2}}{2}+\sqrt{2}\,\sqrt{z^{4}}\right) }\right][x4]=[2z+i√21√(23z2+√2√z4)] totally answer

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4.2% of 60 is PLEASE HELP

Mandarinka [93]

Answer:

2.52

Step-by-step explanation:

4.2% of 60 = 4.2% * 60

4.2% = 0.042

0.042 * 60

2.52

3 0

2 years ago

Read 2 more answers

Please help asap 20 pts

expeople1 [14]

B. If you were to solve for x, the values would be x=1.5275 and x=-1.5275.

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3 years ago

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Write TRUE if the underlined word in the statement is correct.If not , change the underlined word to make it correct.

kobusy [5.1K]

Change the underlined words if it is not correct and write true if it is correct.

<h3>Integers</h3>

1. Positive integers are not whole numbers.

Negative integers are not whole numbers.

2. All whole numbers are integers.

True

3. Zero is the smallest whole number.

True

4. Any whole number greater than zero is a positive integers.

True

5. Fractions and Decimals are not integer.

6. 1 is a counting number and a positive integers.

True

7. Rational number include all integers , fraction, or terminating decimals.

True

8. Any whole number that is greater than 0 is a negative integers.

Any whole number that is less than 0 is a negative integers.

Learn more about integers:

brainly.com/question/10853762

7 0

2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

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3 years ago

Is a shoe store was having a back-to-school sale where you can buy six pairs of shoes for $52.62 if a large family decided to bu

hodyreva [135]

The family would buy the three pairs of shoes for $26.31 because you have to divide $52.62 in half since they bought half the amount of pairs of shoes that are given in the sale.

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3 years ago