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inessss [21]
3 years ago
9

Add or Subtract to Simplify: (4x - 2x3) + (5x3 - 4x + 5) I need the answer ?

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer: =3x^3+5

Step-by-step explanation: Hope this help :D

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Explain how to solve the equation and then check the solution.<br><br> 9 = q – 4
Vika [28.1K]

Assignment: \bold{Solve \ And \ Check \ Equation: \ 9=q-4}

<><><><><><><>

Answer: \boxed{\bold{q=13}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Switch Sides

\bold{q-4=9}

[ Step Two ] Add 4 To Both Sides

\bold{q-4+4=9+4}

[ Step Three ] Simplify

\bold{q=13}

[ Step Four ] Check Your Work

\bold{13 \ - \ 4 \ = \ 9}

[ Step Five ] Question: Is Equation Correct

\bold{Equation \ Is \ Correct, \ Therefore \ q=13}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

5 0
3 years ago
Read 2 more answers
24 students and Jamal's class are wearing tennis shoes there are 30 students in this class your mom says that 70% of this class
slavikrds [6]
No because it would only be 80%
8 0
3 years ago
What is an equation of the line that passes through the point (8, 2) and is parallel to
gayaneshka [121]

Answer:

x+4y is not change because it's parallel what changes is the result 8 + 4 × 2 = 16 so the equation is x + 4y = 16

4 0
3 years ago
Maria compared the slope of the function f(x)=(-6x-21) to the slope of the linear function that fits the values in the table bel
raketka [301]

Answer:

b. both functions have a negative slope

Step-by-step explanation:

The given function is

f(x)=-6x-21


This function is of the form y=mx+b, where m=-6 is the slope and b=-21 is the y-intercept.


We can also determine the slope of the function in the table using any two points, say (0,7)\:and\:(2,6).


The slope formula is given by,

m=\frac{y_2-y_1}{x_2-x_1}.


If (x_1,y_1)=(0,7)\:and\:(x_2,y_2)=(2,6), then,

m=\frac{6-7}{2-0}


m=-\frac{1}{2}.


We can see that both functions have a negative slope.


The correct answer is B.




8 0
3 years ago
Identify the axis of symmetry and vertex of f(x) = –2x2 –2x–1.
Leya [2.2K]

<span>Given the quadratic equation: f(x) = -2x^2 - 2x - 1, the axis of symmetry can be obtained by finding the line that divides the function into two congruent or identical halves. Thus, it should pass through the vertex and is equal to the x-coordinate of the vertex. </span>

<span>Note that a quadratic equation in standard form: y = ax^2 + bx + c, has the vertex located at (h,k) where, h = -b/2a and k is determined by evaluating y at h. In this case, a = -2, b = -2, thus, h = -0.5, k = 0.5. Thus, the vertex is located at (-0.5, 0.5) and the axis of symmetry is at x = -0.5. </span>

4 0
3 years ago
Read 2 more answers
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