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krok68 [10]
3 years ago
12

At which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptote? Check all that apply

Mathematics
2 answers:
pychu [463]3 years ago
6 0

vertical asymptotes: x=-4 , x=1 , x=4

qwelly [4]3 years ago
5 0

Answer:

it is a, c, e, in edge

Step-by-step explanation:

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Answer:

Your answer is A.

Step-by-step explanation:

Looking at the graphing two-equation: y = x^3 -3 and y = x^2+6 are up there, it can help us determine the limit of domain.

The dot is the x<=2 for equation y=x^3-3.

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$28.80

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4.80 x 6 = 28.8

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alexgriva [62]

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RUDIKE [14]

Answer:

area of sector BCD =60/360×π×10²=52.36ft²

a area of sector ADC =90/360×π×√50²=39.27ft²

actual <u>area</u><u> </u><u>=</u><u>5</u><u>2</u><u>.</u><u>3</u><u>6</u><u>ft²-39</u><u>.</u><u>2</u><u>7</u><u>f</u><u>t</u><u>²</u><u>=</u><u>1</u><u>3</u><u>.</u><u>0</u><u>9</u><u>=</u><u>1</u><u>3</u><u>ft²</u>

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