Assuming R and H:
So volume is pir^2 * H = 1500 and H = 1500/(pir^2) while surface area is A= 2pir*H + 2pir^2
A = 2pir(r+h)= 2piR^2 + 2pir*1500/(pir^2)= 2piR^2 + 3000/r
For A to take minimum, get the derivative 4pir - 3000/R^2 and let it be 0
4pir^3 - 3000 = 0
r = cbrt(3000/(4pi)) ≈ 6.20
h = 1500/(pi(6.20)^2) ≈ 12.42
Slope intercept form is y=mx+b. since there is no b term, the y intercept is 0. since there is a 9 in the m term, your slope will be nine. based on those two things, you need a point at (0,0) and (1,9). on the other end, your point will be (-1,-9). then draw a straight line through. hope this helps :)
Answer:
Step-by-step explanation:
Answer:
The dimension of the rectangular gift is 10 by 12 inches so let us find the perimeter of this rectangle.
Perimeter of rectangular gift = 2 (L+ W) = 2 (10 +12) = 44 inches
Since we are to use the same length of ribbon to wrap a circular clock so the perimeter or circumference of the clock should be no more than 44 inches.
2πr = 44
r = 44/2π
r = 7.003
Therefore, the maximum radius of the circular clock is 7 inches.
Answer:
( 5 - 2t ) < - 4
Step-by-step explanation:
The midnight temperature is 5 °C and the temperature is decreasing at the rate of 2°C per hour.
If t is the hours past midnight then after t hours the temperature will be ( 5 - 2t ).
Now, if this temperature is colder than - 4° C, then the inequality can be written as ( 5 - 2t ) < - 4 (Answer)
