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givi [52]
4 years ago
9

When an automobile rounds a curve at high speed, the loading (weight distribution) on the wheels is markedly changed. For suffi-

ciently high speeds the loading on the inside wheels goes to zero, at which point the car starts to roll over. This tendency can be avoided by mounting a large spinning flywheel on the car. (a) In what direction should the flywheel be mounted, and what should be the sense of rotation, to help equalize the loading
Physics
1 answer:
NISA [10]4 years ago
4 0

Answer:

Explanation:

The tendency of the automobile running on a circular path at high speed to turn towards left or right around one of its wheels , is due to torque by centripetal force acting at its centre of mass about that wheel .

Suppose the automobile tends to turn in clockwise direction about its wheel on the outer edge . A rotational angular momentum is created . To counter this effect , we can take the help of a rotating wheel or flywheel . We shall have to keep its rotation in anticlockwise direction so that it can create rotational angular momentum in direction opposite to that created by centrifugal force on fast moving automobile. Each of them will nullify the effect of the other . In this way , rotating flywheel will save the automobile from turning upside down .

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A student is at rest on a stool that may freely spin about its central axis of rotation. As the stool spins, the student holds o
steposvetlana [31]

Answer:

the final speed of the stool is 3.6 rad/s

Explanation:

As we know that there is no external torque on the system

So we can use concept of angular momentum conservation

So we will have

I_1\omega_1 = I_2\omega_2

now we will have

6\times 1.2 = 2\times \omega

\omega = \frac{6 \times 1.2}{2}

\omega = 3.6 rad/s

So the final speed of the stool is 3.6 rad/s

8 0
3 years ago
This image shows a stream of positively charged particles being directed at gold foil. The positively charged particles are call
coldgirl [10]

Answer:

D. When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.

Explanation:

8 0
4 years ago
Read 2 more answers
Which of the following is the most reasonable weight in units of newtons for an average adult?
Oliga [24]

Answer: The reason weight for average adult is 530N

Explanation: The clearly see this answer, let's convert this weight to kg using F=mg

530=m×9.8

g is a constant of 9.8m/s2

We divide both sides by 9.8 to get

54kg then this weight is reasonable for an average adult.

7 0
4 years ago
Read 2 more answers
HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW
ivolga24 [154]

Answer:

The answer is b, friction.

Explanation:

Let's say you're riding your roller skates on the sidewalk. The surface of the sidewalk rubs against your skates, counteracting your movement while you proceed in the opposite direction that the sidewalk is counteracting. The force that causes that is friction.

7 0
3 years ago
A 15.7 kg block is dragged over a rough, horizontal surface by a constant force of 83.1 N
Kay [80]

Answer:

The work done by the 83.1 N force is 4687.5 J.

The magnitude of the work done by the  force of friction is 1187.5 J.

Explanation:

Given:

Mass of the block, m=15.7 kg

Force acting on it, F=83.1 N

Angle of application of force, \theta = 25.7°

Displacement of the block, d=62.6 m

Coefficient of friction, \mu =0.161

Acceleration due to gravity, g=9.8 m/s²

Work done by a force is given as:

Work,W=F\times d\times \cos\theta

So, work done by the constant force is given as:

W_{force}=83.1\times 62.6\times \cos(25.7)\\W_{force}=4687.5\textrm{ J}

Now, in order to find work done by friction, we need to evaluate friction.

For the vertical direction, the net force is zero as there is no vertical motion.

Therefore,

N + F\sin\theta = mg\\ N = mg-F\sin\theta

Frictional force is given as:

f=\mu N=\mu (mg-F \sin \theta)=0.161\times ((15.7\times 9.8)-(83.1\times \sin(25.7))=18.97\textrm{ N}

Now, friction acts in the direction opposite to the displacement. Thus, angle between frictional force and displacement is 180°.

Therefore, work done by friction is:

W_{fric}=f\times d\times \cos\theta_f\\W_{fric}=12.72\times 62.6\times \cos(-180)\\W_{fric}=18.97\times 62.6\times -1\\W_{fric}=-1187.5\textrm{ J}

Negative sign indicates that frictional force is acting opposite to motion.

So, the magnitude of the work done by the  force of friction is 1187.5 J.

8 0
4 years ago
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