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Delvig [45]
4 years ago
10

A car moving at 18 m/s decelerates at -- 2.5 m/s" as it approaches a stop sign.

Physics
2 answers:
yulyashka [42]4 years ago
7 0

Answer:

equation:    Vf=Vo - at

t= (Vf- Vo)/a

t=(0m/s - 18m/s)/(-2.5m/s²)

t= 7.2 s

balandron [24]4 years ago
6 0

<u>Answer:</u>

The car takes 7.2 seconds to come to a complete stop when moving a<u>Explanation:</u>

t 18 m/s decelerates at - 2.5 m/s^2.

From the given statements, we know

Initial Velocity (u) = 18 m/s

Final Velocity (v) = 0 m/s

Acceleration (a) = - 2.5 m/s^2

Applying the 1st Equation of Motion  

v = u + at

and substituting the values, we get

                      t=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{a}}

                          = \frac{0-18}{-2.5}     = 7.2 seconds

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