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defon
4 years ago
9

What is the relationship between the number of loops of wire and the magnitude of the magnetic field?

Physics
1 answer:
AURORKA [14]4 years ago
4 0
Magnitude<span> and direction of the field depends on the shape of the </span>wire<span> and the direction and. Center of the </span>loop<span> is perpendicular to the plane of the </span>loop.<span> Determine the </span>relationship between magnetic field <span>and the </span>number<span> of turns in a coil.</span>
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If you are over-driving your headlights and you see an object ahead, you will_____. be given the right-of-way from other vehicle
SashulF [63]

Answer: not be able to stop in time to miss the object

Explanation:

The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.

When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.

This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.

5 0
4 years ago
Unlike fireflies and glow worms, most objects don't make their own light. So how can you see what's around you?
VashaNatasha [74]
Light reflects off the cornea in the back of your eye thats what makes you see light 
5 0
4 years ago
A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebbl
Leona [35]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

<em>✔ We have: KE = PE (potential energy) </em>

<em>PE = m x g x h </em>

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\  \frac{m_1}{m_2\times 4} = 1 \\ \\  \frac{m_1}{m_2} = 4

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

8 0
3 years ago
A volume of air increases 0.227 m^3 at a net pressure of 2.07 x 10^7 Pa. How much work is done on the air?
aliya0001 [1]

Answer:

The work done on the air is 4.699 x 10⁶ Joules

Explanation:

Given;

increase in air volume, ΔV = 0.227 m³

net pressure of the air, P = 2.07 x 10⁷ Pa

The work done on the air is given by;

W = PΔV

Where;

W is the work done on the air

P is the net pressure

ΔV  is the increase in air volume

Substitute the given values and solve for work done;

W = (2.07 x 10⁷ Pa) (0.227 m³)

W = 4.699 x 10⁶ Joules

Therefore, the work done on the air is 4.699 x 10⁶ Joules

7 0
3 years ago
How many hydrogen atoms could bond with carbon?
aleksley [76]
4 of them to be exact
5 0
4 years ago
Read 2 more answers
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