Question

Two cubic meters of a gas at 303 K are heated at constant pressure until the volume is doubled. What is the final temperature of the gas?

Answer 1

Answer:

$V_1 = {2 \: m}^{3}$

$T_1 = 303 \: k$

$V_2 = 2(V_1) = 2(2) = 4 \: {m}^{3}$

$T_2 = ?$

Here, it's mentioned that the pressure is constant.

By Charles law :

$\implies V \propto T$

$\implies \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}$

$\implies \dfrac{2}{4} = \dfrac{303}{T_2}$

$\implies \dfrac{T_2}{4} = \dfrac{303}{2}$

$\implies T_2 = \dfrac{303 \times 4}{2}$

$\implies T_2 = \dfrac{1212}{2}$

$\implies T_2 = 606 \: k$