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rosijanka [135]
3 years ago
8

How many milliseconds are there in 3.5 seconds

Chemistry
1 answer:
maw [93]3 years ago
6 0
There are 3,500 milliseconds in a second.

One second contains 1,000 milliseconds. Three seconds contain 3,000 milliseconds. Half of three hours, therefore, would contain 3,500 milliseconds.
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A sample of sulfurous acid (H2SO3) has a mass of 1.31 g.
lakkis [162]

Answer:

a) 2 (H+) ions

b) 1 (SO3²-) ions

c) 1.36 × 10^-22 grams.

Explanation:

According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.

Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:

2H+ + SO3²- → H2SO3

Hence;

- there are 2 hydrogen ions (2H+) present in H2SO3.

- there is 1 sulfite ion (SO3²-) present in H2SO3.

c) The mass of one formula unit of H2SO3 is calculated thus:

= 1.008 (2) + 32.065 + 15.999(3)

= 2.016 + 32.065 + 47.997

= 82.08 a.m.u

Since, 1 gram is = 6.02 x 10^23 a.m.u

82.08 a.m.u = 82.08/6.02 × 10^-23

= 13.6 × 10^-23

= 1.36 × 10^-22 grams.

6 0
2 years ago
What name should be used for the ionic compound Cu(NO3)2
Sergeu [11.5K]
<span>Copper(II) nitrate. Hope i cleared your doubt</span>
6 0
2 years ago
Read 2 more answers
Ions of an element (elements with different charges) contain different numbers of what
Vadim26 [7]

Answer:

an ion is an element that has different numbers of protons and electrons

Explanation:

An ion is positive when it has more protons than electrons and negative when it has more electrons than ions.

(Hope this was helpful!) :)

7 0
2 years ago
How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?
castortr0y [4]

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

4 0
2 years ago
How many moles are there in 32.4 grams of Na
Natalija [7]
Divide that my the molar mass which is 23 so 1.4087 g
8 0
3 years ago
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