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Inessa05 [86]
2 years ago
9

Why does carbon dioxide escape when you open the can of soda?

Chemistry
2 answers:
hjlf2 years ago
7 0

Because it was bottled under high pressure and the atmospheric pressure is less. Carbon dioxide only dissolves at higher than normal pressure.

EXPLANATION:

Soda water, like other carbonated beverages, contains carbon dioxide that has dissolved under pressure. When the pressure is released by opening the soda container, the liquid cannot hold as much carbon dioxide, so the excess bubbles out of the solution.

julia-pushkina [17]2 years ago
6 0

Answer:

Explanation: An unopened soda can is virtually bubble-free because the pressure inside the can keeps the carbon dioxide dissolved in the liquid.

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Aleks [24]

Answer:

a)0.816g/l

b)0.241g/l

8 0
2 years ago
What is the pH of a 6.4*10-10 m oh- solution?
egoroff_w [7]
PH: 4.80617997
pOH: 9.1938200
[H+]: 1.562
[OH-] 6.4E-10
Acid
8 0
3 years ago
What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The
pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of isotope 1 = 34.97 amu

Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]

\text{Average atomic mass of element}=32.37amu

Therefore, the average atomic mass of chlorine is, 32.37 amu

8 0
3 years ago
The graphic represents the Milky Way galaxy.
il63 [147K]

Answer:

planets,meteoroids and asteroids  

Explanation:

3 0
3 years ago
Electric power is measured in watts (1 W = 1 J/s). About 95% of the power output of an incandescent bulb is converted to heat an
nlexa [21]

Answer:

9.430 * 10¹⁷ protons per second whill shine on the book from a 62 W bulb

Explanation:

To answer this question, first let's calculate the energy of a single photon with a wavelength (λ) of 504 nm:

E = hc/λ

Where h is Planck's constant (6.626*10⁻³⁴ J·s) and c is the speed of light (3*10⁸ m/s).

E = 6.626*10⁻³⁴ J·s * 3*10⁸ m/s ÷ (504*10⁻⁹m) = 3.944 * 10⁻¹⁹ J.

So now we can make the equivalency for this problem, that

<u>1 proton =  3.944 * 10⁻¹⁹ J</u>

Now we convert watts from J/s to proton/s:

1 \frac{J}{s}*\frac{1proton}{3.944*10^{-19}J}=2.535*10^{18} \frac{proton}{s} = 1 W

Solving the problem, a 62 W bulb converts 5% of its output into light, so:

  • 62 * 5/100 = 3.1 W

3.1 watts are equal to [ 2.535*10¹⁸ proton/s * 3.1 ] = 7.858 * 10¹⁸ proton/s

Of those protons per second, 12% will shine on the chemistry textbook, thus:

7.858 * 10¹⁸ proton/s * 12/100 = 9.430 * 10¹⁷ protons/s

8 0
3 years ago
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