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mel-nik [20]
3 years ago
8

What are the reactants in photosynthesis?

Chemistry
2 answers:
marta [7]3 years ago
7 0

Answer:

The reactants are carbon dioxide, water and solar energy.

Explanation:

Hello!

Let's solve this!

Photosynthesis is a process by which plants convert carbon dioxide, with the help of solar energy into oxygen and glucose to use it as a nutrient.

The reaction is:

6CO2 + 6H2O + sunlight ----> 6O2 + C6H12O6

We conclude that the reactants are carbon dioxide, water and solar energy.

Sveta_85 [38]3 years ago
6 0
Is this about flowers I kinda remeber but nit really if so it's the polination in flowers I'll find out in the morning
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What element is similar to Baruim
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calcium ca

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We can see here that the only element that is on the same group (column) as Ba (Barium) is Calcium (Ca).

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What part of the water cycle involves the leaves of plants
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Answer: The answer to this question is transpiration.

Explanation: I know this answer because i looked it up in a book. The other explanation is I study about this a lot.

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What is metal made out of?
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Explanation:

Scientifically speaking, metals are naturally occurring chemical elements that are typically hard, lustrous, and good conductors of both heat and electricity. Examples include iron, gold, silver, copper, zinc, nickel, etc., but also elements we don't normally think of as metals.

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The volume occupied by 12.5 moles of nitrogen gas at STP is liters.​
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Explanation:

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7.00 of Compound x with molecular formula C3H4 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25c.
beks73 [17]

Answer:

\Delta H_{f,C_3H_4}=276.8kJ/mol

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

\Delta H_{rxn} =- m_wC_w\Delta T

We plug in the mass of water, temperature change and specific heat to obtain:

\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ

Now, this enthalpy of reaction corresponds to the combustion of propyne:

C_3H_4+4O_2\rightarrow 3CO_2+2H_2O

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol

Now, we solve for the enthalpy of formation of C3H4 as shown below:

\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol

Best regards!

7 0
3 years ago
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