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V125BC [204]
4 years ago
6

Calcule la normalidad de una solución

Chemistry
1 answer:
tensa zangetsu [6.8K]4 years ago
5 0

Answer:

si por favor

Explanation:

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klio [65]

The ability to be crushed is a physical property and therefore is the answer.

4 0
4 years ago
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The ph of a 0. 102 m solution of a weak acid (ha) is 1. 15 ka for the weak acid is?
Advocard [28]

The pH of the weak acid is 6.93.

Given,

K= 1.15 *10^{-6}

c=0.102

[H]= K*c= 1.15 *10^{-6} * 0.102= 0.1173 *10^{-6}

p[H]= -log[H]= 6.93

<h3>Weak acid</h3>

A weak acid is one that partially separates into its ions in water or an aqueous solution. A strong acid, on the other hand, completely splits into its ions in water. The conjugate base of a weak acid is also a weak base, and vice versa for the conjugate acid of a weak base. Weak acids have a higher pH than strong acids at the same concentration. Simple arrows pointing left to right are used to represent the reaction of a strong acid ionising in water. On the other hand, a weak acid ionising in water has a double arrow reaction arrow, indicating that both the forward and reverse reactions take place at equilibrium.

Learn more about Weak acid here:

brainly.com/question/22104949

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6 0
1 year ago
The energy level necessary to enable a reaction to a cure is called the activation true or false
matrenka [14]
The correct answer is true. It was introduced by Svante Arrhenius that activation energy is minimum amount of energy needed to be supplied or released for a chemical reaction to proceed. It is the energy needed to overcome for a reaction to occur.
3 0
4 years ago
What pressure is exerted by 0.750 mol of a gas at 0 °C and a volume of 5
kow [346]

Answer: 3.4 atm

Explanation:

Given that:

Volume of gas V = 5L

(since 1 liter = 1dm3

5L = 5dm3)

Temperature T = 0°C

Convert Celsius to Kelvin

(0°C + 273 = 273K)

Pressure P = ?

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Note that Molar gas constant R is a constant with a value of 0.0821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 5dm3 = 0.75 moles x (0.0821 atm dm3 K-1 mol-1 x 273K)

p x 5dm3 = 16.8 atm dm3

p = (16.8 atm dm3 / 5dm3)

p = 3.4 atm

Thus, a pressure of 3.4 atm is exerted by the gas.

7 0
3 years ago
Aldehydes may oxidize to form:
Arlecino [84]
Aldehydes may oxidize to form carboxylic acid <span>exception to oxidizing formaldehyde  with strong oxidizing agent.

HCHO + 3[O] = CO</span>₂ + H₂O
5 0
4 years ago
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