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Radda [10]
3 years ago
15

How can the pH of a solution be calculated if the pOH is known?

Chemistry
2 answers:
daser333 [38]3 years ago
4 0

the answer is d guys


dybincka [34]3 years ago
3 0

Answer:

by subtracting the pOH by 14

Explanation:

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A new element (solid at room temperature) is discovered that has:
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A metalloid is a substance that has both the qualities of a metal and a non metal. Metals conduct electricity and have a high melting point.The element described does not conduct electricity until temperatures are reduced therefore it is not a metal. The fact that conduction occurs when temperatures are reduced means that it is not a non metal because non metals do not conduct electricity at all. Therefore the element is a metaloid because it exhibits some properties of a metal and others of a non mental.

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Please write the process (how soap is made?.......................​
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Soap is created by mixing fats and oils with a base as opposed to detergent which is created by combining chemical compounds in a mixer.

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3 years ago
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A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called
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Answer:
             <span>A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called <em>cis</em> Isomer.

Explanation:
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5 0
3 years ago
Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha
Aleks04 [339]

Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

pH = pKa + log \frac{[Base]}{[Acid]}

We have been given,

pH = 7.5

pKa of carbonic acid = 6.3

Let us plug in the values in Henderson equation to find the ratio Base/Acid.

7.5 = 6.3 + log \frac{[base]}{[acid]}

1.2 = log \frac{[base]}{[acid]}

\frac{[Base]}{[Acid]} = 10^{1.2}

\frac{[Base]}{[Acid]} = 15.8

[Base] = 15.8 \times [Acid]

The total of mole fraction of acid and base is 1. Therefore we have,

[Acid] + [Base] = 1

But Base = 15.8 x [Acid]. Let us plug in this value in above equation.

[Acid] + 15.8 \times [Acid] = 1

16.8 [Acid] = 1

[Acid] = \frac{1}{16.8}

[Acid] = 0.0595

[Acid] = 0.0595 x 100 = 5.95 %

The fraction of carbonic acid present in the blood is 5.95%

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3 years ago
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