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Grace [21]
3 years ago
10

An train car of total mass of 13000 kg is pulling into a station and slowing down with an acceleration of -4.56 m/s^2. Before th

e train pulls into the station, a group of 7 stowaway jump off the train. Each stowaway has a mass of 66 kg. If the braking force on the train remains the same, what will be the acceleration of the train once the stowaways jump out of the train?
Physics
1 answer:
kumpel [21]3 years ago
5 0

Answer:

-4.728 m/s^{2}

Explanation:

F=ma where F is the force, m is the mass of object and a is acceleration

Initial mass is 13000 Kg

Final mass=1300-(66*7)=12538 Kg

F=m\times a=m_i \times a_i=m_f_\times a_f where m_1 and m_f are initial and final mass respectively, a_i and a_f are initial and final acceleration respectively

By substitution

13000\times -4.56=12538\times a_f

a_f=-4.728026799\approx -4.728 m/s^{2}

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Fiesta28 [93]

Answer:

Explanation:

For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit ,  these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.

option b is correct.

With this load, the  fraction of the average power, put out by the source of emf,  delivered to the load can be calculated as follows

Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor.  So the correct option is .7

option D ) is correct.

3 0
4 years ago
An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra
lukranit [14]

Answer:

\frac{dA}{dt} = 28800 \ m^2/year

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Area of a Rectangle: A = lw

<u>Algebra I</u>

  • Exponential Property: w^n \cdot w^m = w^{n + m}

<u>Calculus</u>

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Differentiating with respect to time

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Explanation:

<u>Step 1: Define</u>

Area is A = lw

2w = l

w = 300 m

\frac{dw}{dt} = 24 \ m/year

<u>Step 2: Rewrite Equation</u>

  1. Substitute in <em>l</em>:                    A = (2w)w
  2. Multiply:                              A = 2w²

<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

  1. Differentiate [Basic Power Rule]:                                                                   \frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}
  2. Simplify:                                                                                                           \frac{dA}{dt} = 4w\frac{dw}{dt}

<u>Step 4: Find Rate</u>

<em>Use defined variables</em>

  1. Substitute:                    \frac{dA}{dt} = 4(300 \ m)(24 \ m/year)
  2. Multiply:                        \frac{dA}{dt} = (1200 \ m)(24 \ m/year)
  3. Multiply:                        \frac{dA}{dt} = 28800 \ m^2/year
3 0
3 years ago
Read 2 more answers
Siska hit a golf ball into the air with an initial velocity of 56 feet per second. The height h in feet of the ball above the gr
olasank [31]
To find the time it takes for the ball to reach the given height, we need an equation that relates the height and time it travel which is given to be <span>h=-16t^{2}+56t. We just substitute the height of 49 feet then solve for t. We do as follows:

</span><span>h=-16t^{2}+56t
49 = </span>-16t^{2}+56t
t = 1.75 seconds

Hope this answers the question. Have a nice day.
4 0
3 years ago
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A hot-air balloon is descending at a rate of 2.3 m&gt;s when a pas- senger drops a camera. If the camera is 41 m above the groun
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Answer:

a) t = 2.64s

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Explanation:

If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:

Y = Vo*t - \frac{g*t^{2}}{2}

-41 = -2.3*t - \frac{10*t^{2}}{2}    Solving for t, we get:

t1 = -3.1s     and      t2 = 2.64s We discard the negative time and use the positive one.

The velocity of the camera will be:

Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s

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3 years ago
The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 84 MW at a cruising speed of 35.0 kn
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Answer:

F = 4669.201\,kN

Explanation:

Maximum speed is get at maximum power. Let assume that ship travels at constant speed, the expression for power is equal to:

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Where F and v are the forward force and speed of ship measured in newtons and meters per second, respectively.

The forward force can be determined by clearing it in the expression described above:

F = \frac{\dot W}{v}

F = \frac{84\times 10^{3}\,kW}{(35\,knots)\cdot \left(\frac{0.514\,\frac{m}{s} }{1\,knot} \right)}

F = 4669.201\,kN

4 0
3 years ago
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