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Anon25 [30]
3 years ago
12

A hot-air balloon is descending at a rate of 2.3 m>s when a pas- senger drops a camera. If the camera is 41 m above the groun

d when it is dropped, (a) how much time does it take for the cam- era to reach the ground, and (b) what is its velocity just before it lands? Let upward be the positive direction for this problem.
Physics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

a) t = 2.64s

b) Vf = -28.7m/s

Explanation:

If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:

Y = Vo*t - \frac{g*t^{2}}{2}

-41 = -2.3*t - \frac{10*t^{2}}{2}    Solving for t, we get:

t1 = -3.1s     and      t2 = 2.64s We discard the negative time and use the positive one.

The velocity of the camera will be:

Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s

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dezoksy [38]

Answer:

B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.

Explanation:

As we know that the small gear completes 24 revolutions in 20 seconds

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Since both gears are connected by same chain so both have same linear speed and hence correct answer will be

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4 years ago
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3 years ago
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