Answer:
(a). The electric potential at 1.650 cm is
.
(b). The electric potential at 2.81 cm is
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference






The electric potential at 1.650 cm is
.
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference



The electric potential at 2.81 cm is
.
Hence, This is the required solution.
I know it, X-rays<span>, </span>gamma rays<span> and beta particles are all </span>used<span> in medicine to treat internal organs. X-</span>rays<span> are produced by firing electrons at a metal target and </span>gamma rays<span> are emitted by the nucleus of radioactive atoms. </span>Gamma rays<span> are </span>used<span> to kill cancer cells, to sterilise medical equipment and in radioactive tracers.</span>
Answer:0.00125 watts
Explanation:
resistance=50 ohms
Current=5 milliamps
Current=5/1000 milliamps
Current =0.005 amps
power=(current)^2 x (resistance)
Power=(0.005)^2 x 50
Power=0.005 x 0.005 x 50
Power=0.00125 watts
Mechanical energy can have mechanical systems. The only mechanical system in the list is the compressed spring. A car battery and a glowing incandescent lightbulb have electrical energy, a nucleus of atom has potential (internal) energy.
The minimum value of the coefficient of static friction between the block and the slope is 0.53.
<h3>Minimum coefficient of static friction</h3>
Apply Newton's second law of motion;
F - μFs = 0
μFs = F
where;
- μ is coefficient of static friction
- Fs is frictional force
- F is applied force
μ = F/Fs
μ = F/(mgcosθ)
μ = (250)/(50 x 9.8 x cos15)
μ = 0.53
Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.
Learn more about coefficient of friction here: brainly.com/question/20241845
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