Answer:
12.5 m in 1 second.
Step-by-step explanation:
400/32=12.5
Answer: use search website
Step-by-step explanation: its good
Answer:
Patrick walk approximately <u>112 yards</u>.
Step-by-step explanation:
Given:
A rectangular field is 50 yards wide and 100 yards long.
Patrick walks diagonally across the field.
Now, to find the distance he walk.
Length of the field = 100 yards.
Width of the field = 50 yards.
Now, to get the diagonal distance we put formula:
![Diagonal = \sqrt{length^2+width^2}](https://tex.z-dn.net/?f=Diagonal%20%3D%20%5Csqrt%7Blength%5E2%2Bwidth%5E2%7D)
![Diagonal = \sqrt{100^2+50^2}](https://tex.z-dn.net/?f=Diagonal%20%3D%20%5Csqrt%7B100%5E2%2B50%5E2%7D)
![Diagonal = \sqrt{10000+2500}](https://tex.z-dn.net/?f=Diagonal%20%3D%20%5Csqrt%7B10000%2B2500%7D)
![Diagonal = \sqrt{12500}](https://tex.z-dn.net/?f=Diagonal%20%3D%20%5Csqrt%7B12500%7D)
![Diagonal = 111.80](https://tex.z-dn.net/?f=Diagonal%20%3D%20111.80)
Therefore, Patrick walk approximately 112 yards.
Answer: the decimal should still be there but you don’t want to have a zero so 3.42 would be correcr
Step-by-step explanation:
Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.
![\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathbf%20A%3D%5Cbegin%7Bbmatrix%7D1%26-2%261%5C%5C-3%261%264%5C%5C0%266%268%5Cend%7Bbmatrix%7D)
![\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathbf%20B%3D%5Cmathbf%20A%5E%5Ctop%3D%5Cbegin%7Bbmatrix%7D1%26-3%260%5C%5C-2%261%266%5C%5C1%264%268%5Cend%7Bbmatrix%7D)