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SIZIF [17.4K]
3 years ago
13

A recipe requires 5.5 teaspoons of sugar to make a cheesecake. Which equation shows the number of teaspoons of sugar, y, needed

to make x cheesecakes?
x = 5.5y
y = 5.5 + x
y = 5.5x
x = 5.5 + y
Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0
I believe it is x=5.5y

hope this helps!
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Find the digit 6 in each of these numbers:
Daniel [21]

Answer:

D. The value of the 6 in 364 is 10 times the value of the 6 in 346

Step-by-step explanation:

The digit 6 in 364 is ten times greater than the 6 in 346.

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Jimmy made a scale drawing of his house. The actual dimensions of his house are 50 feet by 100 feet. He used the scale 1 inch :
sleet_krkn [62]

Step-by-step explanation:

10 feet = 1 inch

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7 0
3 years ago
I need help asap someone please help me i dont understand this question so can someone help me
eduard

Answer:

we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

Step-by-step explanation:

Given the expression

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}

=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}

cancel the common factor: 2

=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}

cancel the common factor: p

=\frac{2p+1}{p^2\left(4p^2-1\right)}

=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}

cancel the common factor: 2p+1

=\frac{1}{p^2\left(2p-1\right)}

Expanding

=\frac{1}{2p^3-p^2}

Thus, we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

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Answer:

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