First you want to put them in order from least to greatest. 65, 72, 74, 75, 86, 89, 93, 95, 96, 97, 100. Now you count the numbers on the left and right until you get to the middle, there is an uneven number so therefor you wont have to do any extra math. 65, 72, 74, 75, 86, 89, 93, 95, 96, 97, 100. there is 5 on each side 89 being the median. Now moving onto the mode. You will need all of them for this not taking out the ones of there being multiple. 95, 95, <span>96, 100, </span>86, 75, 75, 75, 74, 72, 89, 97, 93, 65 You need to find the number that there is the most of to find the mode. to do this keep score of how many of each of the numbers there is 95, 95, 96, 100, 86, 75, 75, 75, 74, 72, 89, 97, 93, 65 The most commonly occuring number is 75 in this dataset. Reviewing our answers. In the end the median is 89 and the mode is 75
First let's calculate the mode. The mode is the more repeated data. For our set of data we have that 75 is written three times, the other data are written twice or once. Then, 75 is the mode.
Now, to find the median we need to organize the data from least to greatest.
65 72 74 75 75 75 86 89 93 95 95 96 97 100
as we have an even number of items we take the two middle terms, in this case 86, 89 and find the average value.
(86+89)/2 = 175/2 = 87.5. Then, the median is 87.5.
One minute later at 8:01pm. One lighthouse will flash 3 times (at 20, 40 and 60 seconds)...the other will flash twice (at 30 and 60 seconds). So they will both flash 60 seconds later, at 8:01
b. You would conclude that the differences in the average scores can be traced to differences in the working memory of the two groups.
Step-by-step explanation:
Though the average scores of the two sets could have lead to various conditions, but retentive ability deminishes with respect to an increase in age. With respect to the age of the elderly people involved, it is expected that some of them would not be able to retain information for a long period of time. Thus, their average score is 72%.
The college students' are younger, so it is expected that they should be able to retain more information. That ability is one of the reasons why their average score is 85%.
It can be concluded from the research that the differences in the average scores is probably due to the working memory of the two groups.
