Complete Question
The complete question is shown on the first uploaded image
Answer:
The calcium level that is the borderline between low calcium levels and those not considered low is 
Step-by-step explanation:
From the question we are told that
The mean is 
The standard deviation 
The proportion of the population with low calcium level is 
5% = 0.05
Let X be a X random calcium level
Now the P(X < c) = 0.05
Here P denotes probability
c is population with calcium level at the borderline
Since the calcium level is normally distributed the z-value is evaluated as
The critical value for 0.05 from the standard normal distribution table is
=> 
substituting values
=> 
=>
12 inches go into one foot, so we can calculate the volume of the tank in inches to make the calculations that follow easier. Therefore, to calculate the volume of the tank, we use length x breadth x height = 4 x 2 x 2 = 16 square feet x 12 for square inches = 192 square inches.
Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches.
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
You cannot have a third of a fish, so we round off to the nearest whole number, and we determine that Joseph can put 5 fish in his new aquarium.
Answer:
(16 x^8 - x^3 + 6)/(2 x^3)
Step-by-step explanation:
Simplify the following:
(64 x^8 - 4 x^3 + 24)/(8 x^3)
Factor 4 out of 64 x^8 - 4 x^3 + 24:
(4 (16 x^8 - x^3 + 6))/(8 x^3)
4/8 = 4/(4×2) = 1/2:
Answer: (16 x^8 - x^3 + 6)/(2 x^3)
x = 50
The angles shown are vertically opposite and thus equal
so 3x - 30 = 2(x + 10)
3x - 30 = 2x +20
subtract 2x from both sides
3x - 2x - 30 = 20
x - 30 = 20
add 30 to both sides
x = 20 + 30 = 50
