Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation:
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Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
=
=6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume=
=60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35
Answer:
d = 65
w = 55
Step-by-step explanation:
w + 90 + 35 = 180
w + 125 = 180
w = 55
35 + x = 60 (Vertical angle thm)
x = 25
d + x = 90
d + 25 = 90
d = 65
Answer:
Given the graph 
and 
We have to find the value of k;
Since, g(x) = f(x) +k
Subtract 
from both sides we get;
Add 2 to both sides we get;
Simplify:
or
k = 5
Therefore, the value of k = 5
The main assumption here is that the height at the water level is 0.
So, the answer is given by the solution to the equation
- 16t^2 + 16t + 480 = 0
To solve it, start dividing by -16 to get:
t^2 - t - 30 = 0.
Now factor the left side:
(t - ) (t + ) =0
Find two numbers that add - 1 and its product is -30
(t - 6 ) (t + 5 ) =0
That gives:
t - 6 = 0 ⇒ t = 6 seconds
The other result gives a time negative, which makes not sense for the problem.
Verify substituing 6 in the original equation:
h(6) = -16*6^2 + 16*6 + 480 = -576 + 96 + 480 = 0. Lo cual confirma nuestra solucion.
It toke Rose 6 seconds to hit the water.
Answer:
0,0,0,1,3,5,9 I put it in order
