Answer:
Step-by-step explanation:
y/2 - 4 = x/3 can also be written as 1/2y - 4 = 1/3x
slope intercept form is y = mx + b
1/2y - 4 = 1/3x....multiply entire equation by 6, to get rid of fractions
3y - 24 = 2x ...add 24 to both sides
3y = 2x + 24....divide both sides by 3
y = 2/3x + 6 <===
y -3 = 2(x-4)
Use distributive property on the right side:
y - 3 = 2x -8
Add 3 to both sides:
y = 2x -5
The answer is A.
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221