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Alchen [17]
3 years ago
6

Find the circumference of the circle in terms of it.​

Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

37.6991 cm

Step-by-step explanation:

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767 runners entered a race. 305 more entered before the race started. How many runners are in the race? A 1072​
boyakko [2]
1072 is the answer duh
4 0
3 years ago
3). Let g(x) = x^4 - 6x^3 + 13x^2 - 24x + 36. Find all complex zeros and multiplicities, if 2i is a complexzero. Apply the conju
lutik1710 [3]
g(x)=x^4-6x^3+13x^2-24x+36

4 0
1 year ago
What is the slope intercept of y/2-4=x/3
Ierofanga [76]

Answer:

Step-by-step explanation:

y/2 - 4 = x/3 can also be written as 1/2y - 4 = 1/3x

slope intercept form is y = mx + b

1/2y - 4 = 1/3x....multiply entire equation by 6, to get rid of fractions

3y - 24 = 2x ...add 24 to both sides

3y = 2x + 24....divide both sides by 3

y = 2/3x + 6 <===

8 0
3 years ago
Which is the standard form of y-3=2(x-4) <br> (A) Y=-2x-5<br> (B)2x-5<br> (C)2x+y=-5<br> (D)2x-y=5
pantera1 [17]

y -3 = 2(x-4)

Use distributive property on the right side:

y - 3 = 2x -8

Add 3 to both sides:

y = 2x -5

The answer is A.

4 0
3 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
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