Answer:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
Out of 100 people sampled, 42 had kids.
This means that 
99% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Answer:
y=mc
Step-by-step explanation:
Answer:
49.5
Step-by-step explanation:
99 divided by 2
If you have 5 pieces of something you split it up into 2 for each and then slip the last one into two.
There are a total of 16 movies to choose from and 6 of them are comedy. This means that you have a 38% of choosing comedy. But the chances of you not choosing comedy is 62%. And since your friend is also choosing, the chance of neither of you not choosing is cut in half.
So, the final answer of neither of you choosing comedy is 31%
(I don't know whether it's dependent or independent)
