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Degger [83]
3 years ago
7

A shipping company charges a $6 flat fee for a package, plus a fee based on the weight of the package. The company charges $1.25

per pound, plus an additional $0.50 for every pound over 9 pounds. Adrian plans on sending a package that is over 5 pounds. He has $20 to spend on shipping. What is the maximum number of pounds that his package could be? Enter your answer as a decimal
Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer: 11.2 pounds is the max weight of the package he can have.

Step-by-step explanation: $20 - $6 is $14. $14 divided by 1.25 is 11.2.

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Erik buys 2.5 pounds of cashews.If each pound of cashews $7.70,how much will he pay for the cashews???I put Erik will pay $49250
Fittoniya [83]
The answer should be $ 19.25. All you have to do is $7.70 * 2.5 which = $19.25
3 0
3 years ago
Read 2 more answers
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
Anyone knows this?!? ​
IRINA_888 [86]

Answer:

(0.84, 0.88)

Step-by-step explanation:

if you round 0.875 you get 0.88

8 0
2 years ago
On which number line are -3 and its opposite shown?
netineya [11]

Answer:

it would be 3

Step-by-step explanation:

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4 years ago
Add me on sc <br> tommyplanksnaps
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Answer:

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