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3 years ago

Convert 30 feet per second into yards per minute

Mathematics

2 answers:

diamong [38]3 years ago

8 0

Answer:

600 yd/min

Step-by-step explanation:

$\displaystyle{\frac{30\text{ ft}}{1\text{ sec}}\times\frac{1\text{ yd}}{3\text{ ft}}}\times\frac{60\text{ sec}}{1\text{ min}}=\frac{1800\text{ yd}}{3\text{ min}}=600\frac{\text{yd}}{\text{min}}$

olga55 [171]3 years ago

6 0

Answer:

30 feet converted into yards per minute would come out to 600 yards per minute

Step-by-step explanation:

multiply speed value by 20

30x20=600

Hope this helped :)

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ss7ja [257]

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Bonjour je suis en 3 ème pouvez vous m'aider s'il vous plaît une voiture met 2 h 30 pour faire 200 km 1. Calculer sa vitesse moy

Lemur [1.5K]

Répondre:

Explication étape par étape:

Vitesse = Distance / Temps

Distance donnée = 200 km

Durée = 2 h 30

Convertir le temps en heures

Depuis 60 minutes = 1h

2 heures 30 minutes = 2+ (30/60)

2h30 = 2 + 1/2 hors

2 heures 30 minutes = 2,5 heures

Vitesse en km / h = 200 km / 2,5 h

Vitesse en km / h = 80 km / h

D'où sa vitesse moyenne en km / h est de 80 km / h

a) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3h15

Temps = 3 15/60 h

Durée = 3,25 h

Distance = 80 * 3,25

Distance parcourue en 3h15 = 260 km

b) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 42 minutes

Durée = 42/60 h

Distance = 80 * 42/60

Distance = 3360/60

Distance = 56 km

Distance parcourue en 42 minutes = 56 km

c) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3 h 36 minutes

Temps = 3 36/60 h

Durée = 3,6 h

Distance = 80 * 3,6

Distance = 288 km

Distance parcourue en 3 h 36 min = 288 km

d) Distance donnée = 540 km

Vitesse = 80 km / h

Temps = Distance / Vitesse

Heure = 540/80

Temps = 6,75 heures

Par conséquent, le temps nécessaire pour parcourir 540 km est de 6,75 heures

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Answer:
_______________________________________________
1) 72 $\pi$ cm² / min. ;
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2) 192 $\pi$ cm² / min.
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Explanation:
____________________________________________

Area of a circle: A = $\pi$ r² ;

Rate of change of Area is: da/dt = 2 $\pi$ r (dr/dt) ;

Given: dr/dt = 3 cm / min.
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Problem 1)
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Problem 2)
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