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4 years ago

Find the radius of the circle if the center is at (1,2) and the point (-5,-6) lies on the circle

Mathematics

2 answers:

Tju [1.3M]4 years ago

5 0

Answer:

sqrt{52}=r

Step-by-step explanation:

The equation of a circle has the following form:

where (h,k) is the center of a circle with radius r.

Our equation is:

We will find the radius by inputting the point (-5,6) which lies on the circle and solving for r.

Read more on Brainly.com - brainly.com/question/11831904#readmore

padilas [110]4 years ago

4 0

Answer:

sqrt{52}=r

Step-by-step explanation:

The equation of a circle has the following form:

where (h,k) is the center of a circle with radius r.

Our equation is:

We will find the radius by inputting the point (-5,6) which lies on the circle and solving for r.

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The owner of a snow cone stand used 1/4 gallon of syrup to make 16 cherry snow cones. She used the same amount of syrup in each.

Andreas93 [3]

Answer:

4 gallons

Step-by-step explanation: for each gallon she used one

5 0

3 years ago

Read 2 more answers

Find the integral, using techniques from this or the previous chapter. ∫x(8-x)3/2 dx

Soloha48 [4]

Answer:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

Step-by-step explanation:

For this case we need to find the following integral:

$\int x(8-x)^{3/2}dx$

And for this case we can use the substitution $u = 8-x$ from here we see that $du = -dx$ , and if we solve for x we got $x = 8-u$ , so then we can rewrite the integral like this:

$\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)$

And if we distribute the exponents we have this:

$\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du$

Now we can do the integrals one by one:

$\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C$

And reordering the terms we have"

$\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C$

And rewriting in terms of x we got:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

And that would be our final answer.

8 0

3 years ago

Which of the following values "completes the square," or creates a perfect square trinomial, for x2 + 6x + ___?

jekas [21]

To create a perfect square trinomial, halve the x coefficient, square it, and then add that value.

In the case of x² + 6x, we would have 6 to get 3, then square 3 to get 9.
We would add 9 to make a perfect square trinomial.

Why this works
A perfect square trinomial is designed to factor to some value (x+n)².
When you FOIL this you get x² + 2nx + n².
As you can see, if you wanted to find the value of that n², you could take that x coefficient 2n, halve it to get n, and then square it to get n²!

7 0

3 years ago

F(x)= √x-5. find f-2

rodikova [14]

For this case we have:

Be a function of the form $y = f (x)$