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3 years ago

Which functions are increasing? Select all answers that are correct.

Mathematics

2 answers:

Lostsunrise [7]3 years ago

6 0

The top left and bottom right

Ad libitum [116K]3 years ago

6 0

Answers are A and D hope this helps you

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What is the value of sin 0 given that (3-4) is a point on the terminal side of 0

Effectus [21]

Using trigonometric relations, we will see that:

sin(θ ) = -0.8

<h3>How to get the sine of the angle?</h3>

For any point (x, y), the angle between the positive x-axis and the ray that connects the origin with the point (x, y) is:

θ = Atan(y/x)

In this case, the point is (3, -4), then the angle is:

θ = Atan(-4/3) = -53.13°

Then the sine of theta is:

sin(θ = -53.13°) = -0.8

If you want to learn more about trigonometric functions:

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8 0

2 years ago

What is the answer to 5 x 7/8

ASHA 777 [7]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Please help! Correct answer only, please! I need to finish this assignment this week. What are the dimensions of the matrix show

Katena32 [7]

Answer:

3 x 5

Step-by-step explanation:

The dimension of a matrix is normally represented in form of:

<u>number of rows</u> x <u>number of columns</u>

In the given matrix, there are 3 rows and 5 columns.

=> The dimension of this matrix is 3 x 5

=> Option D is correct

Hope this helps!

5 0

3 years ago

Area of the base of cuboid shaped tank is 8400 cm. When 420 liters of water is put into the tank. find the height of the water i

Oksi-84 [34.3K]

Answer:

hope this helps you get a good grades

4 0

3 years ago

In a random sample of 80 teenagers, the average number of texts handled in one day is 50. The 96% confidence interval for the me

Naily [24]

Answer:

Standard deviation of the sample = 17.421

Step-by-step explanation:

We are given that in a random sample of 80 teenagers, the average number of texts handled in one day is 50.

Also, the 96% confidence interval for the mean number of texts handled by teens daily is given as 46 to 54.

So, sample mean, $xbar$ = 50 and Sample size, n = 80

Let sample standard deviation be s.

96% confidence interval for the mean number of texts, $\mu$ is given by ;

96% confidence interval for $\mu$ = $xbar \pm 2.0537*\frac{s}{\sqrt{n} }$

[46 , 54] = $50 \pm 2.0537*\frac{s}{\sqrt{80} }$

Since lower bound of confidence interval = 46

So, 46 = $50 - 2.0537*\frac{s}{\sqrt{80} }$

50 - 46 = $2.0537*\frac{s}{\sqrt{80} }$

s = $\frac{4*\sqrt{80} }{2.0537}$ = 17.421

Therefore, standard deviation of the sample is 17.421 .

3 0

4 years ago