9514 1404 393
Answer:
98
Step-by-step explanation:
The numbers of tiles are 5, 8, 11. This is an arithmetic sequence with a first term of 5 and a common difference of 3. The n-th term is ...
an = a1 +d(n -1) . . . . . for first term a1 and common difference d
This sequence has n-th term ...
an = 5 +3(n -1)
Then the 32nd term is ...
a32 = 5 + 3(32 -1) = 5 +93 = 98
Figure 32 will have 98 tiles in it.
15+0.50x=25+0.25x
-0.25x -0.25x
15+0.25x=25
-15 -15
0.25x=10
Then divide by 0.25 on each side
x=40
Simplify 8/3c to 8c/3
8c/3 - 2 = 2/3 c - 12
Simplify 2/3 c to 2c/3
8c/3 - 2 = 2c/3 - 12
Multiply both sides by 3
8c - 6 = 2c - 36
Simplify 8c - 6 - 2c to 6c - 6
6c - 6 = -36
Add 6 to both sides
6c = -36 + 6
Simplify -36 + 6 to -30
6c = -30
Divide both sides by 6
c = -30/6
Simplify 30/6 to 5
<u>c = -5</u>