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3 years ago

What does (x2−50x−600)÷(x−60) equal?

Mathematics

2 answers:

Natalka [10]3 years ago

8 0

Answer:

x+10 x ≠ 60

Step-by-step explanation:

(x^2−50x−600)

----------------------

(x−60)

Factor the numerator

(x-60)(x+10)

-------------------

(x-60)

Cancel the like terms

x+10

Rus_ich [418]3 years ago

6 0

Answer:

x + 10

Step-by-step explanation:

= x2 - 60x + 10x - 600

= x(x - 60) + 10(x - 60)

= (x + 10)(x - 60)

= (x - 60)(x +10)/x - 60)

= (x - 60) gets canceled

= x + 10

Hope this helps, and please mark me brainliest if it does!

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2 years ago

Read 2 more answers

Seven times a number is less than or equal to a quantity that is 24 less than that same

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Answer:

$7x\leq x-24$

Here, $x$ denotes the required number.

Step-by-step explanation:

Let $x$ denotes the required number that satisfies the following condition.

''seven times a number is less than or equal to a quantity that is 24 less than that same number''

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3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

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2 years ago