<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
33% of 279 is equivalent to multiplying them: 33% × 279.
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
50-x=3(24-x)
50-x=72-3x
2x=22
x=11years ago when kate's father was 3 times as old as kate=11
Answer:
82
Step-by-step explanation:
Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.
The sum of 4 consecutive numbers:
1st = x
2nd = x + 1
3rd = x + 2
4th = x + 3
The sum of 4 consecutive number is 326.
1st + 2nd + 3rd + 4th = 326
x + (x + 1) + (x + 2) + (x + 3) = 326
Combine like terms:
4x + 6 = 326
Then we subtract 6 from both sides to isolate 4x:
4x + 6 - 6 = 326 - 6
4x = 320
Then we divide both sides by 4 to isolate x:
4x/4 = 320/4
x = 80
So the first number is 79
Now to get the second, let's just add 1.
80 + 1 = 81
Let's check if our answer would be correct:
80 + 81 + 82 + 83
= 326
Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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